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swat32
3 years ago
15

True or False Friction can be reduced by lubricating or changing the shape of objects

Chemistry
2 answers:
Alborosie3 years ago
5 0

Answer:

True

Explanation:

If you cover cup in soap it will be a lot more slippery than it was before, if you reshaped a car wheel to have less treads then it would have much less friction.

Aleonysh [2.5K]3 years ago
4 0
True
Hope this help:)
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All of the following need to be present for a plant to do photosynthesis except
KonstantinChe [14]
Oxygen is a by-product of photosynthesis thus it is not needed for photosynthesis to occur.  

Light is needed to provide the energy needed as photosynthesis is endothermic and is also needed to ionise the water molecule to get hydroxide and hydrogen ions and carbon dioxide is what is reduced to starch.
8 0
4 years ago
The bronsted-lowry definition views an acid-base reaction as a _____ transfer reaction.
Effectus [21]

The bronsted-lowry definition views an acid-base reaction as a proton transfer reaction.

Johannes Nicolaus Brnsted and Thomas Martin Lowry independently developed the Brnsted-Lowry theory, also known as the proton theory , which states that any compound that can transfer a proton to another compound is an acid, and the compound that accepts the proton is a base.

A proton is a nuclear particle with a unit positive electrical charge; it is denoted by the symbol H+. Similar to how a substance can only act as a base when a acid is present, a substance can only act as an acid when a base is present. Additionally, an acidic material transforms into a basic when it loses a proton.

In addition, when a basic substance obtains a proton, it generates an acid known as the conjugate acid of a base, and when an acidic substance loses a proton, it forms a base known as the conjugate base of an acid.

Learn more about acid here;

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7 0
1 year ago
Is the following equation balanced? Why or why not?<br> N, + 6H2 → 2NHO
Fiesta28 [93]

Answer:

No

Explanation:

There is only one Nitrogen on the left side while there are 2 on the right. Also there is zero oxygen on the left side and two on the right. The amounts of hydrgen arent equal to each side either.

6 0
4 years ago
Consider the synthesis of water as shown in Model 3. A container is filled with 10,0 g of H, and
kondor19780726 [428]

Answer:

Oxygen, O₂ is the limiting reactant

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2H₂ + O₂ —> 2H₂O

Next, we shall determine the masses of H₂ and O₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 2 × 2 = 4 g

Molar mass of O₂ = 16 × 2 = 32 g/mol

Mass of O₂O from the balanced equation = 1 × 32 = 32 g

SUMMARY:

From the balanced equation above,

4 g of H₂ reacted with 32 g of O₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

4 g of H₂ reacted with 32 g of O₂.

Therefore, 10 g of H₂ will react with

= (10 × 32)/4 = 80 g of O₂.

From the calculations made above, we can see that a higher mass (i.e 80 g) of O₂ than what was given (i.e 5 g) is required to react completely with 10 g of H₂. Therefore, O₂ is the limiting reactant.

5 0
3 years ago
What fraction of a Sr-90 sample remains unchanged after 87.3 years
jolli1 [7]
The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>t_{1/2} = 28.8 years

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{87.3 years}{28.8 years}
⇒ n=3.03
<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^3
⇒x= \frac{1}{8}<span>
</span>
8 0
4 years ago
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