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2 years ago

Write the slope-intercept equation of the line with a slope of - 7 and a y-intercept of (0.-12)

Mathematics

1 answer:

Korvikt [17]2 years ago

5 0

Answer:

y= -7x + (-12)

Step-by-step explanation:

that is the equation

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-x + 5y = 13<br>x - y = 15

aivan3 [116]

Answer:

x-y-15=15-15

x-y-15=0

hope this helps :)

3 0

2 years ago

Read 2 more answers

Question 1 (1 point)

taurus [48]

Answer:

question no 1:slope=5

Step-by-step explanation:

let(x=5andy=8)(a=7andb=18)

now

slope=(b-y)/(a-x)=(18-8)/(7-5)=5

5 0

2 years ago

Read 2 more answers

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

2 years ago

I need the answer for part b

Softa [21]

Answer:

4/4

Step-by-step explanation:

1/4 plus 1/4 plus 2/4 is 4/4

4 0

1 year ago

Part of a shape is drawn.

frosja888 [35]

Answer:

The points of the rotated shape are: (4, 1), (5, 3), (4, 4), (2, 1), (1, 3), (2, 4)

Step-by-step explanation:

From the part of the shape we can see and the symmetry, the missing points are:

(-2, -1)

(-1, -3)

(-2, -4)

Rotation 180° about the origin transforms the point (x, y) into (-x, -y). Applying this rule to our figure, we get:

(-4, -1) -> (4, 1)

(-5, -3) -> (5, 3)

(-4, -4) -> (4, 4)

(-2, -1) -> (2, 1)

(-1, -3) -> (1, 3)

(-2, -4) -> (2, 4)

6 0

2 years ago