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coldgirl [10]
3 years ago
9

I need ASAP!! Find CU. If necessary, round answers to 4 decimal places

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

The correct answer for this equational ratio is x = 5

Step-by-step explanation:

In order to calculate for x, we must create the necessary ratios

\frac{16}{20} = \frac{45-5x}{5x}

Cross multiply to get

900 - 100x = 80x

900 = 180x

x = 5

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The image of a point after a –90° rotation about the origin is (–4, 7). What are the coordinates of the preimage?.
ahrayia [7]
The coordinated of the preimage would be :

x  = x cos θ + y sin θ

y = x sin θ + y cos θ

where 

x = -4  
y = 7
θ = -90

hope this helps
4 0
3 years ago
Point A (5, 6) is translated 3 units left and 5 units up, what are<br> the coordinates of A prime?
Radda [10]

Answer:

A' = (8, 11)

Explain:

5+3=8 & 6+5=11

3 0
3 years ago
You are a bank teller, and your cash drawer
matrenka [14]

Answer:

I dont know.

Step-by-step explanation:

3 0
3 years ago
What is the magnitude (size) of 6.8?
lidiya [134]

Answer:

C. 6.8, because |6.8|= 6.8

Step-by-step explanation:

The magnitude of a directed number is a property that turns the number to a positive of its value. Thus, the magnitude of a negative number equals its positive value. Examples:

Find the magnitude of the following numbers:

i. -20

ii. 10

iii. -5

iv. 2

The magnitudes of the numbers can be expressed as:

i. |-20| = 20

ii. |10| = 10

iii. |-5| = 5

iv. |2| = 2

Therefore, the magnitude of 6.8 = 6.8, because |6.8|= 6.8.

7 0
2 years ago
If the distance from A (5,6) to B (1, b) is twice the distance from B to
Nimfa-mama [501]

Answer:

The possible values of b are -2.944 and -9.055, respectively.

Step-by-step explanation:

From statement we know that AB = 2\cdot BC. By Analytical Geometry, we use the equation of a line segment, which is an application of the Pythagorean Theorem:

AB = 2\cdot BC

\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}} = 2\cdot \sqrt{(x_{C}-x_{B})^{2}+(y_{C}-y_{B})^{2}} (1)

Where:

x_{A}, x_{B}, x_{C} - x-Coordinates of points A, B and C.

y_{A}, y_{B}, y_{C} - y-Coordinates of points A, B and C.

(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2} = 4\cdot (x_{C}-x_{B})^{2}+4\cdot (y_{C}-y_{B})^{2}

Then, we expand and simplify the expression above:

x_{B}^{2}-2\cdot x_{A}\cdot x_{B} +x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot (x_{C}^{2}-2\cdot x_{C}\cdot x_{B}+x_{B}^{2})+4\cdot (y_{C}^{2}-2\cdot y_{C}\cdot y_{B}+y_{B}^{2})

x_{B}^{2}-2\cdot x_{A}\cdot x_{B} + x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot x_{A}^{2}-8\cdot x_{C}\cdot x_{B}+4\cdot x_{B}^{2}+4\cdot y_{C}^{2}-8\cdot y_{C}\cdot y_{B}+4\cdot y_{B}^{2}

If we know that x_{A} = 5, y_{A} = 6, x_{B} = 1, y_{B} = b, x_{C} = 1 and y_{C} = -3, then we have the following expression:

1 -10 +25 +b^{2} -12\cdot b+36  = 100 -8 +4 +36+24\cdot b +4\cdot b^{2}

b^{2}-12\cdot b +52 = 4\cdot b^{2}+24\cdot b +132

3\cdot b^{2}+36\cdot b +80 = 0

This is a second order polynomial, which means the existence of two possible real solutions. By Quadratic Formula, we have the following y-coordinates for point B:

b_{1} \approx -2.944, b_{2} \approx -9.055

In consequence, the possible values of b are -2.944 and -9.055, respectively.

8 0
3 years ago
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