The condition is called phytoplankton because algae are microscopic, need sunlight and nutrient, water to survive.
<h3>What is phytoplankton?</h3>
Phytoplankton refers to microscopic marine algae and they are also called microalgae.They are similar to terrestrial plants in that they contain chlorophyll and require sunlight in order to live and grow. Most phytoplankton are very buoyant and float in the upper part of the ocean, where sunlight enter the water and they get the sunlight to produce food.
Algae photosynthesized,that is they use sunlight in the presence of chlorophyii and carbondioxide to produce food and oxygen.
Therefore, The condition is called phytoplankton because algae are microscopic, need sunlight and nutrient, water to survive.
Learn more about phytoplankton here.
brainly.com/question/18091244
Answer:
6 moles
Explanation:
Take a look at the balanced chemical equation for this synthesis reaction
N
2(g]
+
3
H
2(g]
→
2
NH
3(g]
Notice that you have a
1
:
3
mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.
So, if you have
2
moles of nitrogen taking part in the reaction, you will need
2
moles N
2
⋅
3
moles H
2
1
mole N
2
=
6 moles H
2
Answer:
1.78
Explanation:
1mole produce 18g/x will produce 32g then the answer is 1.78moles
An ionic compound forms when a metal bonds with a non-metallic element. Metals usually form the cation and non-metal anions. Chromium has an oxidation number of +3 in the compound and charge on hydroxide ion is -1.
Cation here is
Anion is the hydroxide ion
So the formula of the compound will be: . The compound has one chromium atom and two hydroxide ions.
Therefore, there will be one Chromium atom per each chromium hydroxide compound.
Answer:
Explanation:
Moles of NaCl :
Given, Mass of NaCl = 72.24 g
Molar mass of NaCl = 58.44 g/mol
The formula for the calculation of moles is shown below:
Thus,
NaCl is a strong salt. So, moles of chloride ion = 1.2361 moles
Volume = 0.862 L