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V125BC [204]
3 years ago
12

Consider the ionic compound that is the combination of the Chromium (III) and hydroxide ions. How many chromium atoms would be p

resent in this compound?
Chemistry
1 answer:
kobusy [5.1K]3 years ago
6 0

An ionic compound forms when a metal bonds with a non-metallic element. Metals usually form the cation and non-metal anions. Chromium has an oxidation number of +3 in the compound and charge on hydroxide ion is -1.

Cation here is Cr^{3+}

Anion is the hydroxide ion OH^{-}

So the formula of the compound will be: Cr(OH)_{3}. The compound has one chromium atom and two hydroxide ions.

Therefore, there will be one Chromium atom per each chromium hydroxide compound.

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A sample of C3H8 has 6.72 x 10^24 H atoms. <br> What is the total mass of the sample?
gregori [183]
The answer is 492.8 g


1. Calculate a number of moles of a sample.
2. Calculate a molar mass of C3H8.
3. Calculate a mass of the sample. 

1. Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance: 6.023 × 10²³ units per 1 mole    

6.023 × 10²³ atoms : 1 mol =6.72 × 10²⁴ atoms : n

n = 6.72 × 10²⁴ atoms * 1 mol : 6.023 × 10²³ atoms = 1.12 × 10 mol = 11.2 mol


2. Molar mass (Mr) of C3H8 is sum of atomic masses (Ar) of its elements:

Ar(C) = 12 g/mol

Ar(H) = 1 g/mol

Mr(C3H8) = 3 * Ar(C) + 8 * Ar(H) = 3 * 12 + 8 * 1 = 36 + 8 = 44 g/mol



3. Mass (m) of a sample is number of moles (n) multiplied by molar mass (Mr) of C3H8:

m = n * Mr = 11.2 mol * 44 g/mol = 492.8 g

6 0
3 years ago
The molar mass of Beryllium (Be)
e-lub [12.9K]
The molar mass of Beryllium is 9.012182 u (symbol I can't put down) 0.000003 U
8 0
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How do you do these?
Agata [3.3K]

Solve these problems like weighted averages:

The first one:

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The second one:

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If you think about it, these answers make sense. 6.924 is much closer to 7 than to 6 (since there's a lot more lithium-7 than there is lithium-6). 10.8 is closer to 11 than to 10.


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Explanation:

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