Answer : You can make 4.68 moles of SO₂
Explanation:
Step 1 : Write balanced equation.
S₈ can combine with oxygen to form SO₂ gas. The balanced equation for this reaction is written below.
Step 2 : Find moles of S₈
The formula to calculate mol is
Molar mass of S₈ is 256.5 g/mol
we have 0.585 mol of S₈
Step 3: Use mole ratio to find moles of SO₂
The mole ratio of S₈ and SO₂ can be found using balanced equation which is 1:8
That means 1 mol of S₈ can form 8 moles of SO₂.
Let us use this as a conversion factor to find moles of SO₂
Therefore we have 4.68 moles of SO₂
The question is incomplete. The complete question is:
The partial pressure of 
in your lungs varies from 25 mm Hg to 40 mm Hg. What mass of can dissolve in 1.0 L of water at 25 degree Celsius if the partial pressure of is 40 mm Hg.
Answer: 
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:
where,
= Henry's constant = 
= partial pressure = 39 mm Hg = 0.051 atm (760mmHg=1atm)
Putting values in above equation, we get:
Hence, of can dissolve in 1.0 L of water at 25 °C if the partial pressure of is 39 mm Hg
Answer: H3PO4(aq)+3NaOH(aq)→Na3PO4(aq)+3H2O(l)
Explanation:
The answer is: XY₂ .
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For example:
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MgCl₂
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Answer:
160 mL
Explanation:
Given data:
Molarity of NaOH = 0.105 M
Volume of H₂SO₄ = 40.0 mL (40.0/1000 = 0.04 L)
Molarity of H₂SO₄ = 0.210 M
Volume of NaOH required = ?
Solution:
Number of moles of of H₂SO₄:
Molarity = number of moles / volume in L
0.210 M = number of moles / 0.04 L
Number of moles = 0.210 mol/L × 0.04 L
Number of moles = 0.0084 mol
now we will compare the moles of H₂SO₄ with NaOH.
H₂SO₄ : NaOH
1 : 2
0.0084 : 2/1×0.0084 = 0.0168 mol
Volume of NaoH:
Molarity = number of moles / volume in L
0.105 M = 0.0168 mol / Volume in L
Volume in L = 0.0168 mol / 0.105 M
Volume in L = 0.16 L
Volume in mL:
0.16 L × 1000 mL/ 1L
160 mL
