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2 years ago

Can someone help me on 1 and 2

Chemistry

2 answers:

uranmaximum [27]2 years ago

7 0

Growth is 1. Reproduction is 2.

Because in the years the boy grew that is a characteristic of life. And the Cat giving birth is reproduction because it is when new life is made

pav-90 [236]2 years ago

6 0

I believe 1 is growth and 2 is reproduction. Hope this helps.

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A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple

miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

$\frac{V}{T}=const.$

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where in this problem we have:

$V_1=490 mL$ is the initial volume of the gas

$T_1=-35.0^{\circ} + 273 = 238 K$ is the initial temperature

$T_2=42.0^{\circ}+273=315 K$ is the final temperature

Solving for V2, we find the final volume of the gas:

$V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL$

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3 years ago

A student observes chloroplasts in the micrograph of a cell.

allochka39001 [22]

Answer:

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2 years ago

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Carbon-13 is an isotope. It has 6 protons and _____. 13 neutrons 7 neutrons 7 electrons 13 electrons

vovangra [49]

Answer:

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Explanation:

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3 years ago

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A coffee-cup calorimeter initially contains 125 g water at 24.28C. Potassium bromide (10.5 g), also at 24.28C, is added to the w

iren2701 [21]

Answer:

The solution is given below

Explanation:

Heat, q= mc∆T

q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C

q= -1619.75J

NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.

Enthalpy Change, ∆H = 1619.75 7/ 10.5 g

= 154.26 J/g

No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr

=10.5g/119gmol-1

=0.088 mol

∆H= 1619.75 J/ 0.088 mol

= 18.41 kJ/mol

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Nonamiya [84]

Answer:

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