Answer:
Step-by-step explanation:
Given that a dairy scientist is testing a new feed additive. She chooses 13 cows at random from a large population of cows. She randomly assigns nold = 8 to get the old diet, and nnew = 5 to get the new diet including the additive.
From the data given we get the following
N Mean StDev SE Mean
Sample 1 8 43 5.1824 1.832
Sample 2 5 73 21.0832 9.429
df = 11
Std dev for difference = 13.3689
a) Yes the two are independent. The two sets of cows randomly chosen are definitely independent. Paired means equal number should be there and homogeneous conditions should be maintained.
b) Enclosed
c) Comparison of two means is the test recommended here. Because independent samples are used.\
d) Test statistic= -3.1233
(because of unequal variances we use that method)
95% confidence interval = ( -56.6676 , -3.3324 )
p value <0.05 our alpha
So reject null hypothesis.
The two means are statistically significantly different.
9514 1404 393
Answer:
(b) 112.2 ft
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
For the given geometry, this becomes ...
tan(65°) = (height above eye level)/(50 ft)
Then we have ...
(height above eye level) = (50 ft)tan(65°) = 107.2 ft
Adding the height of eye level will give us the height of the building.
building height = (eye level height) + (height above eye level)
building height = (5 ft) + (107.2 ft)
building height = 112.2 ft
Answer:
1. Blue = 8 votes
2. Green = 4 votes
3. Yellow = 6 votes
4. Red = 2 votes the first 2 votes one
5. Pink = 2 votes the second one that says 2 votes.
Step-by-step explanation:
okay I understand this.
You just use the colors from above and fill them in in order.
We are given with the following:
Effective annual interest, i = 0.0425
Future worth, F = $25000
Number of years, n = 18
We use the formula to solve for the present worth of the money:
P = F / (1 + i)^n
P = 25000 / (1 + 0.0425)^18
P = 11818.73
The closest answer is:
<span>b.
$11,820</span>
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
