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pychu [463]
2 years ago
11

Describe the arrangement and movement of the octane molecules when it is a liquid​

Chemistry
1 answer:
Allisa [31]2 years ago
8 0

Answer:

Particles in a liquid move randomly and can slide past each other but they don't move far away from each other. Particles in liquids are close together, rolling over each other and arranged randomly. Particles in a solid vibrate in all directions but cannot move out of their fixed positions.

Explanation:

yuh

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Which state of matter is Na OH(s)​
Shalnov [3]

Explanation:

SOLID

Sodium hydroxide exists in the solid phase at room temperature. You would find it in the lab as hemispherical white solid pellets. The phase of a substance depends on temperature and pressure. As you heat a solid, it will melt and change to the liquid phase.

4 0
3 years ago
Hydrogen chloride and oxygen react to form chlorine and water, like this:
leva [86]

Answer:

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

Explanation:

This is the reaction:

4 HCl (g) + O₂ (g)  ⇒ 2 Cl₂ (g)  + 2 H₂O(g)

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

8 0
3 years ago
Read 2 more answers
For a reaction at equilibrium, which change can increase the rates of the forward and reverse reactions?a decrease in the concen
Monica [59]
Question requires a change resulting in an increase in both forward and reverse reactions. Now lets discuss options one by one and see there impact on rate of reactions.

1) <span>A decrease in the concentration of the reactants:
                                                                                       
When concentration of reactant is decreased it will shift the equilibrium in Backward direction, so resulting in increasing the backward reaction and decreasing the forward direction. Hence, this option is incorrect.

2) </span><span>A decrease in the surface area of the products:
                                                                               Greater the surface Area greater is the chances of collision and greater will be the rate of reaction. As the surface area of products is decreased it will not favor the backward reaction. Hence again this statement is incorrect according to given statement.

3) </span><span>An increase in the temperature of the system:
                                                                             An increase in temperature will shift the reaction in endothermic side. Hence, if the reaction is endothermic, an increase in temperature will increase the rate of forward direction or if the reaction is exothermic it will increase the rate of reverse direction. Hence, this option is correct according to given statement.

4) </span><span>An increase in the activation energy of the forward reaction:
                                                                                                   An increase in Activation energy will decrease the rate of reaction, either it is forward or reverse. So this is incorrect.

Result:
          Hence, the correct answer is,"</span>An increase in the temperature of the system".
7 0
3 years ago
Please help me, I am confused on this.
weeeeeb [17]

Answer:

The First choice is correct

Explanation:

That is the closest example of what is shown

4 0
3 years ago
Read 2 more answers
A concentration cell consisting of two hydrogen electrodes (PH2 = 1 atm), where the cathode is a standard hydrogen electrode and
Lunna [17]

The pH of the unknown solution is 3.07.

<u>Explanation:</u>

<u>1.Find the cell potential as a function of pH</u>

From the Nernst Equation:

Ecell=E∘cell−RT /zF × lnQ

where

R denotes the Universal Gas Constant

T denotes the temperature

z denotes the moles of electrons transferred per mole of hydrogen

F denotes the Faraday constant

Q denotes the reaction quotient

Substitute the values,

E∘cell=0   lnQ=2.303logQ

E0cell=−2.30/RT /zF × log Q

Solving the equation,

<u>2. Find the Q  value</u>

Q=[H+]2prod pH₂, product/ [H+]2reactpH₂, reactant

Q=[H+]^2×1/1×1=[H+]2

Taking the log

logQ= log[H+]^2=2log[H+]=-2pH

From the formula,

Ecell=−2.303RT /zF× logQ

E cell= 2.303 × 8.314 CK mol (inverse)  × 298.15

K × 2pH /2×96 485  C⋅mol

( inverse)

E cell= 0.0592 V × pH

<u>3. Finding the pH value</u>

E cell= 0.0592 V × pH

pH = E cell/ 0.0592 V= 0.182V/ 0.0592V

pH=3.07

The pH of the unknown solution is 3.07.

7 0
3 years ago
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