Answer:
NH4+ is the conjugate acid of the base NH3.
Explanation:
Answer:
The correct answer is <em>It is a ratio of the concentrations in a reaction.</em>
Explanation:
⇒ It is a ratio of the concentrations in a reaction.
This sentence is true because the equilibrium constant is calculated from the product of the concentration of the reaction products divided into the product of the concentrations of the reactants, each concentration raised by the stoichiometric coefficient. For example, for the following reaction:
aA + bB → cC + dD
The equilibrium constant is expressed as:
![K = \frac{[C]^{c}[D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%20%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%7D)
⇒ It remains the same at different temperatures.
The sentence is false because the equilibrium constant changes with the temperature. In general, an endothermic reaction is favored by the increment of temperature (the equilibrium shifts to the right side) and disfavored with the decrease in temperature (shifts to the left).
⇒ It is represented by the symbol H.
This sentence is false because the equilibrium constant is represented with the letter K.
⇒ Its value is always close to 1.
It is not true because the equilibrium constant can be a number below or above 1.
K < 1 ⇒ there is more concentration of reactants at equilibrium
K > 1 ⇒ there is more concentration of products at equilibrium
13. Nt
14. St
15. St
16. At
17. Nt
Answer:
1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi
Explanation:
Let's do the required conversions:
1 mol of atoms has 6.02×10²³ atoms
Bi → 1 mol of bismuth weighs 208.98 grams
Let's do the rules of three:
6.02×10²³ atoms are the amount of 1 mol of Bi
4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles
1 mol of Bi weighs 208.98 g
7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g
Answer:
D
Explanation:
Without gravity, any object wont go to the ground, and without a magnetic field, a compass cant be used for navigation.