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TiliK225 [7]
3 years ago
7

What is the abbreviation for the element with atomic number 11?

Chemistry
2 answers:
Andrei [34K]3 years ago
8 0

Answer:

Na

Explanation:

VikaD [51]3 years ago
5 0

Answer:

Sodium (Na) has atomic number 11.

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The answer is 2035.44
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A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
natima [27]

Answer:

A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.515 g/L at 0.745 atm .

(4x^2)x

Kc= -----------

(A-2x)^2

PV=nRT

n/v = P/RT = .745/(0.0821)(334+273) = .01495

To Find the initial molarity of NO2

(mol/L)(g/mol) + (mol/L)(g/mol) + (mol/L)(g/mol)= g/L

Thus:

46(A-2x) + 2x(30) + 32x = .515 g/L

46A-92x+60x+32x = .515

46A=.515

A=.01120 M

Using the total molarity found

(A-2x)+2x+x = .01495 M

A+x=.01495

Plug in A found into the above equation:

.01120+x = .01495

x=.00375

Now Plug A and x into the original Equilibrium Constant Expression:

(4x^2)x

Kc= -----------

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Kc = 0.000014

Explanation:

3 0
3 years ago
If I leave 750 mL of a 0.40 M sodium chloride solution uncovered on a windowsill
mel-nik [20]

Answer:

B. 0.5 molar

Explanation:

Given data:

Initial concentration = 0.40 M

Initial volume = 750 mL

Final volume =750  -  150 mL = 600 mL

Final concentration = ?

Solution:

Molarity is the number of moles of solutes in litter of solvent. In given problem it is stated that when the solution is uncovered solvent evaporate it means molarity is changed. we can calculate the new molarity with the following formula.

C₁V₁ = C₂V₂

C₁ = initial concentration

V₁ = initial volume

C₂ = final concentration

V₂ = final volume

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.40 M × 750 mL = C₂ × 600 mL

300 M.mL / 600 mL = C₂

0.5 M = C₂

5 0
3 years ago
The reaction 2HgO (s)→2Hg (I)+O2 (g) has a percent yield of 50%. You want to produce 100 g of Hg.
nevsk [136]

The mass of HgO needed for the reaction is 216 g

The correct answer to the question is Option C. 216 g

We'll begin by calculating the theoretical yield of Hg.

  • Actual yield of Hg = 100 g
  • Percentage yield = 50%
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Theoretical yield = Actual yield / percentage yield

Theoretical yield = 100 / 50%

Theoretical yield of Hg = 200 g

Finally, we shall determine the mass of HgO needed for the reaction.

2HgO → 2Hg + O₂

Molar mass of HgO = 201 + 16 = 217 g/mol

Mass of HgO from the balanced equation = 2 × 217 = 434 g

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Mass of Hg from the balanced equation = 2 × 201 = 402 g

From the balanced equation above,

402 g of Hg were produced from 434 g of HgO.

Therefore

200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.

Thus, 216 g of HgO is needed for the reaction.

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By what number do you multiply 588 to get your weight in newtons on jupiter?
erica [24]

The number that will be multiplied by 588 to get one's weight in Newtons is 2.5 considering that the mass of the individual is 60kg.

<h3>How to calculate weight?</h3>

Weight is the force on an object due to the gravitational attraction between it and the Earth (or whatever astronomical object it is primarily influenced by).

The weight of an object can be calculated by multiplying the mass of the object by acceleration due to gravity of the location.

According to this question, we would consider an individual with a mass of 60kg. The acceleration due to gravity on Jupiter is 24.5 m/s².

Weight = 60kg × 24.5 m/s² = 1470N

This means that the number to be multiplied by 588 to get weight of 1470N is 2.5.

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