Answer:
13 m/s
Explanation:
The computation of the final velocity is shown below;
We know that
v^2 = u^2 + 2as
Here v represent the final velocity
u denotes the initial velocity
a denotes the acceleration
And, s denotes the displacement
So, the final velocity is
v^2 = (5)^2 + 2(8)(9)
= sqrt(25 + 144)
= sqrt(169)
= 13 m/s
Acceleration=Final velocity-Initial velocity /time.
Acceleration=a=4m/s².
Initial velocity= u= 44m/s
Final velocity=v= let it be v, since we are to look for the final velocity.
Time=t=10seconds.
Mathematically:
a=v-u/t
Substituting the givens into the equation.
4=v-44/10
cross multiply.
4×10 = v-44
40=v-44
40+44=v
v=84m/s
Answer:
2.5705594546378 mol
Explanation:
Used this calculator
http://www.endmemo.com/chem/mmass.php
Electric Field Strength E = Force F/ Charge q
E = F/q
Force , F = E*q
But charge on an electron q = 1.6 * 10⁻¹⁹ C
E = 3 * 10³ N/C from the question.
Force F = 3* 10³ * 1.6 * 10⁻¹⁹
F = 4.8 * 10⁻¹⁶ N.
Electrostatic force F = 4.8 * 10⁻¹⁶ N
The following is eawual if 87 is 2 times the size
