Since acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then
0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x
⇒ ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m
Impulse is change in momentum. The initial momentum was
0.1kg*11m/s=1.1kg m/s.
The second momentum is 0.1*(-8.8m/s)=-0.88 (since it's moving backward now)
The difference is P1-P2 = 1.1-(-0.88)=1.98kg m/s
No, if the car were moving sideways, then the forces used would be on the horizontal axis. So the weight equation would be extraneous, unless one is determining the net force through an inclined plane
Answer:
Those objects are called transparent objects...
Explanation:
If only some light can pass through them ,it is called translucent....
If no light can pass through them ,it is called opaque.
Answer:
The new pressure is 4 times of the initial pressure.
Explanation:
Given that,
The pressure of an ideal gas is 4 atm.
We need to find the change in the pressure of the gas if the temperature by a factor of 4.
We know that,
PV = nKT ....(1)
P = pressure, V = volume, T = temperature
Let P' is the new pressure of the gas. So,
P'V= nK(4T) ......(2)
Dividing equation (1) and (2) we get :
It means that the new pressure is 4 times of the initial pressure.
