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UkoKoshka [18]
3 years ago
10

An object accelerates at a rate of 8 m/s² over a displacement of 9 m. If the object started with a velocity of 5 m/s, what is it

s final velocity?
Physics
1 answer:
Crank3 years ago
8 0

Answer:

13 m/s

Explanation:

The computation of the final velocity is shown below;

We know that

v^2 = u^2 + 2as

Here v represent the final velocity

u denotes the initial velocity

a denotes the acceleration

And, s denotes the displacement

So, the final velocity is  

v^2 = (5)^2 + 2(8)(9)

= sqrt(25 + 144)

= sqrt(169)

= 13 m/s

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navik [9.2K]

Hybrid

<u>Hybrid</u> modified the concept by adding an internal combustion engine and marketing hybrids that were part electric and part gas powered.

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  • There are numerous hybrid configurations.
  • A hybrid vehicle might, for instance, get its energy from burning gasoline while alternating between an electric motor and a combustion engine.
  • Although they have primarily been employed for rail locomotives, electrical vehicles have a long history of integrating internal combustion and electrical transmission, like in a diesel-electric power-train.
  • Because the electric drive transmission directly substitutes the mechanical gearbox rather than serving as an additional source of motive power, a diesel-electric powertrain does not meet the definition of a hybrid.
  • Only the electric/ICE hybrid car type was readily accessible on the market as of 2017.
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  • Another ran in series, using one source to supply power solely and the other to supply electricity.
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3 0
2 years ago
I WILL GIVE BRAINLIEST TO THE BEST OR FIRST ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
s344n2d4d5 [400]
1 Weather-Weather is the state of the atmosphere, describing for example the degree to which it is hot or cold, wet or dry, calm or stormy, clear or cloudy

2 How much money do you make?

3
 a Without the atmosphere, average temperature on Earth would be freezing! Below zero to be exact!

b The atmosphere protects us and animals from dangerous radiation from the Sun. Ultraviolet radiation is basically invisible rays of energy created by the sun.

cAlso, the atmosphere provides oxygen for humans and animals to breathe and C02 (Carbon dioxide) for plants. 

4 warmth 

5 yes it is The water on our Earth today is the same water that’s been here for nearly 5 billion years. Only a tiny bit of it has escaped out into space. As far as we know, new water hasn’t formed either.

That means there’s a very high chance the water in your glass is what thirsty dinosaurs were gulping about 65 million years ago.

7 0
3 years ago
A ski jumper has a mass of 59.6 kg. She is moving with a speed of 23.4 m/s at a height of 44.6 meters above the ground. Determin
Daniel [21]

Hello!

Use the formula:

M = k * p

Data:

M = Mechanic energy

k = Kinetic energy

p = Potencial energy

Descomposing:

M = (0,5*mv²) + (mgh)

Replacing:

M = (0,5 * 59,6 kg * (23,4 m/s)²) + (59,6 kg * 9,81 m/s² * 44,6 m)

M = 16317,28 J + 26076,54 J

M = 42393,82 J

The mechanic energy is <u>42393,82 Joules.</u>

7 0
3 years ago
8. Noticing how much food is on your lunch<br> tray is a quantitative observation because
zhenek [66]

Answer:

you are making an observation that uses numbers.

Explanation:

5 0
3 years ago
where σ(t) and σ(0) represents the time-dependent and initial (i.e., time =0) stresses, respectively, and t and τ denote elapsed
lesya [120]

Answer:

E_r(6)=4.35614\ MPa

Explanation:

\epsilon = Strain = 0.49

\sigma _0 = 3.1 MPa

At t = Time = 32 s \sigma = 0.41 MPa

\tau = Time-independent constant

Stress relation with time

\sigma=\sigma _0exp\left(-\frac{t}{\tau}\right)

at t = 32 s

0.41=3.1exp\left(-\frac{32}{\tau}\right)\\\Rightarrow exp\left(-\frac{32}{\tau}\right)=\frac{0.41}{3}\\\Rightarrow -\frac{32}{\tau}=ln\frac{0.41}{3}\\\Rightarrow \tau=-\frac{32}{ln\frac{0.41}{3}}\\\Rightarrow \tau=16.0787\ s

The time independent constant is 16.0787 s

E_{r}(t)=\frac{\sigma(t)}{\epsilon_0}

At t = 6

\\\Rightarrow E_{r}(6)=\frac{\sigma(6)}{\epsilon_0}

From the first equation

\sigma(t)=\sigma _0exp\left(-\frac{t}{\tau}\right)\\\Rightarrow \sigma(6)=3.1exp\left(-\frac{6}{16.0787}\right)\\\Rightarrow \sigma(6)=2.13451

E_r(6)=\frac{2.13451}{0.49}\\\Rightarrow E_r(6)=4.35614\ MPa

E_r(6)=4.35614\ MPa

6 0
3 years ago
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