Answer:
mass of the second ball is 0.379m
Explanation:
Given;
mass of first ball = m
let initial velocity of first ball = u₁
let final velocity of first ball = v₁ = 0.45u₁
let the mass of the second ball = m₂
initial velocity of the second ball, u₂ = 0
let the final velocity of the second ball = v₂
Apply the principle of conservation of linear momentum;
mu₁ + m₂u₂ = mv₁ + m₂v₂
mu₁ + 0 = 0.45u₁m + m₂v₂
mu₁ = 0.45u₁m + m₂v₂ -------- equation (i)
Velocity for elastic collision in one dimension;
u₁ + v₁ = u₂ + v₂
u₁ + 0.45u₁ = 0 + v₂
1.45u₁ = v₂ (final velocity of the second ball)
Substitute in v₂ into equation (i)
mu₁ = 0.45u₁m + m₂(1.45u₁)
mu₁ = 0.45u₁m + 1.45m₂u₁
mu₁ - 0.45u₁m = 1.45m₂u₁
0.55mu₁ = 1.45m₂u₁
divide both sides by u₁
0.55m = 1.45m₂
m₂ = 0.55m / 1.45
m₂ = 0.379m
Therefore, mass of the second ball is 0.379m (where m is mass of the first ball)
Answer:
A
Explanation:
The region with the least population growth will have the shallowest line. That would be Europe. Between 2000 and 2020, the line is basically flat, while the others are rising.
Answer is A.
Answer:
the answer to this question is
<em>The</em><em> </em><em>Same</em><em> </em>
<em>newton's</em><em> </em><em>law</em><em> </em><em>#3</em>
Explanation:
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em>
Answer:
The answer for this is Green Rectangle.
Explanation:
The hue after effects theory suggests that as you glance away at a white background, you can see a <em>Green Rectangle</em> after looking at a bright red rectangle for a period of time.
All this is an after-image consequence. Afterimage is a form of optical illusion in which, even after exposure to the original image has ended, an picture appears to appear momentarily.
Answer:
The solid ball and hollow ball both will reach the bottom with the same speed.
Explanation:
The speed of the solid and hollow balls is independent of the mass and the radius. A solid and hollow ball experience same speed on a given incline.
The speed can be calculated as
v = √(10/7)gh
where g is gravitational acceleration and h is the height
sinθ = h/L
h = L*sinθ
h = 3*sin(35)
h = 1.72 m
v = √(10/7)*9.8*1.72
v = 4.91 m/s
Both balls will reach the bottom at the speed of 4.91 m/s.
