Answer:
Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
Step-by-step explanation:
Feets of fencing = 14
Perimeter = 14
Let x = Length y = width
Perimeter = 2(x + y)
For x = 1
2(1 + y) = 14
1 + y = 7
y =6
Area of rectangle ; x *y = 1 * 6 = 6 ft²
For x = 2
2(2 + y) = 14
2 + y = 7
y = 5
Area of rectangle ; x *y = 2 * 5 = 10 ft²
For x = 3
2(3 + y) = 14
3 + y = 7
y =4
Area of rectangle ; x *y = 3 * 4 = 12 ft²
For x = 4
2(1 + y) = 14
4 + y = 7
y = 3
Area of rectangle ; x *y = 4 * 3 =12 ft²
Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
The answer is the answer is C and F.
This is found by inserting the equation above into the quadratic formula or -b plus or minus the square root of b^2 - 4ac over 2a.
With that, you find that the first number is a -3, which eliminates choices B and D.
Then, solving the 4ac portion, you find that inside the square root the number is 29, which gives you the last two answer choices.
Hope this helps!
You changed the mixed numeral into a fraction correctly.
Now you need to multiply the fractions.
Multiply the numerators together, and multiply the denominators together.
Now we could multiply out the numerator and denominator, and then we'd need to reduce the fraction, but before we multiply, we see there is a factor of 5 both in the numerator and in the denominator, so we can reduce before we multiply.
Answer:
38 students
Step-by-step explanation:
251 students minus the students traveled in cars =228 divide that by six buses and your outcome will be 38 students
