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Hoochie [10]
3 years ago
14

Join pls need help with home work 643 294 6371 Pass 1234

Chemistry
2 answers:
UNO [17]3 years ago
8 0

Answer:

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Explanation:

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Gekata [30.6K]3 years ago
8 0
Is this zoom or your phone number?
You might be interested in
What element is this? How do you know?
Gnom [1K]

This element is Helium. This is because it has two protons and two neutrons in its nucleus. this makes it have the atomic mass of approximately four atomic mass units. It also has two electrons in the first energy level. . It is therefore a noble gas since this is the only energy level and it obeys the 2n² rule for the filling of energy levels. n in this case is 1 making the maximum number of electrons in the first energy level to be 2.

8 0
4 years ago
How many moles of strontium chloride are included in 20 mL of 0.2 M strontium<br> chloride?
Archy [21]

Answer:

Number of moles of strontium chloride = 0.004 mol

Explanation:

Given data:

Molarity = 0.2 M

Volume = 20 mL

Moles of strontium chloride = ?

Solution;

Formula:

Molarity = number of moles of solute / volume in litter

Now we will convert the volume into litter.

20 mL/1000mL × 1 L

0.02 L

Now we will put the values in formula:

Molarity = number of moles of solute / volume in litter

Number of moles of solute = Molarity × volume in litter

Number of moles of solute = 0.2 mol/L × 0.02 L

Number of moles of solute = 0.004 mol

4 0
3 years ago
B. A reaction occurs between the vinegar and the<br>alkaline sting. What is this reaction called?​
alexandr402 [8]
It’s called neutralization. The alkali has neutralized the acid by taking away the H+ ions and then turning them into water.
8 0
3 years ago
If 1.00 g of reactant a is mixed with 2.00 g of reactant b, what is the theoretical yield of product d, in grams (g)? the molar
WARRIOR [948]

The chemical reaction is as follows:

a+b\rightarrow d

Mass of reactant a is 1 g and molar mass is 94 g/mol. Converting mass into number of moles as follows:

n=\frac{m}{M}=\frac{1g}{94 g/mol}=0.0106 mol

Now, 1 mole of reactant a gives 1 mole of product d thus, 0.0106 mol of reactant a gives 0.0106 mol of product d.

Molar mass of product d is 125 g/mol, converting number of moles into mass as follows:

m=n×M=0.0106 mol×125 g/mol=1.33 g

Similarly, molar mass of reactant b is 118 g/mol and mass is 2 g, converting mass into number of moles,

n=\frac{m}{M}=\frac{2g}{118 g/mol}=0.017 mol

1 mol of reactant b gives 1 mol of product d thus, 0.017 mol will give 0.017 mol of product d.

Converting number of moles into mass as follows:

m=n×M=0.017 mol×125 g/mol=2.12 g

Here, reactant that produces lesser product is limiting reactant and the amount of product it forms is theoretical yield.

Therefore, theoretical yield is 1.33 g.


6 0
3 years ago
Sufficient strong acid is added to a solution containing na2hpo4 to neutralize one-half of it. what will be the ph of this solut
Ivahew [28]
Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)

Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
14 - pHi - log 2 = 14 - pH
In terms of pHi,
pH = pHi + log 2
3 0
3 years ago
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