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3 years ago

Join pls need help with home work 643 294 6371 Pass 1234

Chemistry

2 answers:

UNO [17]3 years ago

8 0

Answer:

???

Explanation:

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Gekata [30.6K]3 years ago

8 0

Is this zoom or your phone number?

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Consider the reaction represented by the equation?2SO2(g) + O2(g) 2SO3(g).?For the system at chemical equilibrium, which of the

rewona [7]

Answer:

b. The amount of SO3(g) decreases and the value for K increases.

Explanation:

Hello,

In this case, for the given reaction:

$2SO_2(g) + O_2(g)\rightleftharpoons 2SO_3(g)$

The change in the stoichiometric coefficient is:

$\Delta \nu=2-2-1=-1$

In such a way, since the reagents have more moles than the products, based on Le Chatelier's principle, if the volume is increased, the side with more moles is favored. In addition, since the formation of reagent is favored, K is diminished based on the law of mass action shown below:

$K=\frac{[SO_3]_{eq}^2}{[SO_2]_{eq}^2[O_2]_{eq}}$

Therefore the answer is:

b. The amount of SO3(g) decreases and the value for K increases.

Best regards.

3 0

4 years ago

Please help this will determine my grade so I beg help me out and my grade

Lelu [443]

Answer:

C: checking your email

Explanation:

I believe that C would be impossible, as you cannot use wireless networks without radio waves

7 0

3 years ago

Read 2 more answers

HELP ME PLS ASAP ILL GIVE BRAINLY

____ [38]

Answer: Latitudes closer to the equator receive more solar energy than latitudes away from the equator

Explanation:

4 0

3 years ago

The total pressure in a tank is filled with a mixture of gases : Oxygen, Helium, and Argon is 15.3 atm. The P(He) = 3.2 atm, P(O

Viktor [21]

Answer:

4.7 atm

Explanation:

From the question given above, the following data were obtained:

Total pressure (P) = 15.3 atm

Pressure of Helium, P(He) = 3.2 atm

Pressure of Oxygen, P(O) = 7.4 atm

Pressure of Argon, P(Ar) =?

The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:

P = P(He) + P(O) + P(Ar)

15.3 = 3.2 + 7.4 + P(Ar)

15.3 = 10.6 + P(Ar)

Collect like terms

15.3 – 10.6 = P(Ar)

4.7 = P(Ar)

P(Ar) = 4.7 atm

Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm

4 0

3 years ago

A certain reaction at equilibrium has more moles of gaseous products than of gaseous reactants.(b) Write a statement about the r

mojhsa [17]

To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>Briefly explained</h3>

When the amount of gaseous reactant is greater than the amount of gaseous product, where $n_{products} < n_{reactants}$ ,

then = $K_p < K_c$

It's because $\Delta n$ is negative, which places (RT) in the denominator. This is how the equation will now appear.

$K_p = K_c(RT)^{-\Delta n} = \frac{ K_c}{(RT)^{\Delta n}}$

Here you can observe the value of $K_c$ is greater than $K_p$ . To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about equilibrium

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6 0

2 years ago