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murzikaleks [220]
3 years ago
5

Why are angiosperms better able to produce offspring better than other plants

Chemistry
1 answer:
podryga [215]3 years ago
3 0
They have more oxygen
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4. Since water possess a partially positive and a negative end, we refer to it as?
Elanso [62]

Answer:

A polar molecule

Explanation:

8 0
2 years ago
. ______________ will slow down alcohol absorption. Sleeping well Food in the large intestine Being happy and relaxed Food in th
solong [7]

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Food in the stomach that is high in protein will dilute absorption of alcohol in your stomach :) therefore always drink with food in your stomach, just drinking alchol without food will have serious consequences on helath.

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7 0
3 years ago
What happens when Sulphuric acid is added to into Barium Chloride solution?​
vladimir1956 [14]

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please give me brainlist and follow

Explanation:

When dilute sulphuric acid is added to barium chloride solution, barium sulphate is formed as a precipitate and hydrogen chloride is formed in aqueous solution.

6 0
3 years ago
1) How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7g Fe? Show your work.
klasskru [66]
1.) is157.7 g
<span>moles Fe = 209.7 g/ 55.847 g/mol=3.75 
the ratio between Fe and CO is 2 : 3 
moles CO = 3.75 x 3 /2 =5.63 
mass CO = 5.63 mol x 28.01 g/mol=157.7 g

2.) is </span><span>1.06 moles 
</span>48.7/23 = 2.12 moles sodium 
<span>2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles </span>
1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen.

3.) is 91.8 
<span>8.3 moles H2S x (2 moles H2O / 2 moles H2S) = 8.3 moles H2O = theoretical amount produced. </span><span>8.3 moles H2O x (18.0 g H2O / 1 mole H2O) = 149 g H2O produced theoretically. </span><span>% yield = (actual amount produced / theoretical amount) x 100 = (137.1 g / 149 g) x 100 = 91.8 </span>
6 0
3 years ago
Read 2 more answers
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
pogonyaev

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

5 0
3 years ago
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