Hi there!

We can begin by multiplying by its conjugate:

Simplify using the identity:


Take the square root of the expression:

Multiply again by the conjugate to get a SINGLE term in the denominator:

Simplify:

Use the above trig identity one more:

Cancel out sinA:

Split the fraction into two:

Recall:

Simplify:

Complete Question
A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.
Write and solve an equation to find the weights of the cat and the dog.
Answer:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Step-by-step explanation:
Let's represent:
Weight of cat = x
Weight of Dog = y
A dog weighs 2 pounds less than 3 times the weight of a cat.
y = 3x - 2........ Equation 1
The dog weighs twenty two more pounds than the cat
y = x + 22....... Equation 2
The equation is given as:
y = y
3x - 2 = x + 22
Collect like terms
3x - x = 22 + 2
2x = 24
x = 24/2
x = 12 pounds
Solving for y using any of the equations:
y = 3x - 2
y = 3 × 12 - 2
y = 36 - 2
y = 34 pounds
Therefore:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Answer:
4.
Step-by-step explanation:
2+2 equals 4. Plus sign: + you add two on both sides, therefor you get 4 as your answer.
Answer:
18 units
Step-by-step explanation:
The centroid is located 1/3 the distance from the midpoint of a side to the opposite vertex. That means ...
CG = 2·DG = 6 + DG
Then
DG = 6 . . . . . . subtract DG from the above equation
Of course, ...
CD = CG +DG = 2·6 +6
CD = 18
Answer:
The distance between the light and the actor's face is 29.24 ft
Step-by-step explanation:
In the attached photo, you can see where the hypotenuse, the opposite side, and and adjacent side are located from the given angle measurement which is 70°. Our known side length is 10 ft which is our adjacent side and our variable is the hypotenuse. So, we will use <u>cos</u>.

Let's plug in our numbers and variable.

Since our hypotenuse is a variable, we are going to flip the equation so we can find the value of the hypotenuse which is also our variable.

Divide 10 by (cos)70.
<em>x = 29.24</em>
So, the hypotenuse is 29.24 feet which shows the distance between the light and the actor's face.