A force of 5.5N is applied to an object. The moment arm for the force is 0.84 m, the torque produced by the force is <u>4.62N-m</u>.
A force applied perpendicularly to a lever multiplied by its distance from the lever's fulcrum (the length of the lever arm) is its torque. We can find the torque from a force by taking the perpendicular component of that force and multiplying by the magnitude of the R vector where this R vector is the vector that points from the axis to the point where the force is applied.
To calculate torque produced by the force, we have-
Torque= forcexmoment arm
T = fxd
T =5.5Nx0.84m
T=4.62N-m.
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F-mg=ma
F-(12kg)(9.8m/s^2)=(12kg)(1.2m/s^2)
F-117.6N=14.4N
F=132 Newtons
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Increases exponentially is your correct answer
Answer:
The depth of the water at this point is 0.938 m.
Explanation:
Given that,
At one point
Wide= 16.0 m
Deep = 3.8 m
Water flow = 2.8 cm/s
At a second point downstream
Width of canal = 16.5 m
Water flow = 11.0 cm/s
We need to calculate the depth
Using Bernoulli theorem
Put the value into the formula
Hence, The depth of the water at this point is 0.938 m.
