The stretch of the spring is
The constant of the spring is k=15 N/m, so we can find the force produced by the weight by using Hook's law:
Rocket thrust equation
= ( mass flow rate of fuel burnt ) X (Velocity of gas ejected ) + ( Exit Pressure - Outdoor Pressure ) X ( Area of exhaust )
In this case, we can assume the exit pressure = outdoor pressure and since area of exhaust is not given, it can be assumed to be negligible.
In this case, by Newton 3rd’s law,
Force exerted by gas on rocket
= Force exerted by rocket on gas
= (10kg/s) X (5 x 10^3 m/s)
= 5 x 10^4 N
With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x 
N and 66 degrees
ELECTRIC FORCE (F)
F = 
Where K = 9 x 
N
/
The distance between 
and 
can be calculated by using Pythagoras theorem.
d = 
d = 46.7 cm = 0.467 m
For force 
, substitute all the parameters into the formula above
= (9 x x 3 x 1)/
= 2.7 x 
/0.218
= 1.24 x N
For force 
, substitute all the parameters into the formula above
= (9 x x 3 x 4)/
= 1.08 x /0.1089
= 9.92 x N
For force 
, substitute all the parameters into the formula above
= (9 x x 3 x 2)/
= 5.4 x /0.1089
= 4.96 x N
Summation of forces on Y component will be
= - Sin 45
= 9.92 x - 1.24 x Sin 45
= 9.04 x N
Summation of forces on X component will be
= - Cos 45
= 4.96 x - 1.24 x Sin 45
= 4.08 x N
Net Force = 
Net force = 
Net force = 9.9 x N
The direction will be
Tan ∅ = /
Tan ∅ = 9.04 x / 4.08 x
Tan ∅ = 2.216
∅ = 
(2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
The Neutron-to-Proton Ratio. Hope this helps Sorry if it's wrong I'm a little rusty on Physics.
69 i agree with her hope this helps
