Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Biggest is all nine's
smallest is 1 then zeroes
greatest
999999
smallest
10000
Answer:
2 - √3
Step-by-step explanation:
tan45 = 1
tan60 = √3
2 tan 45 - tan 60
2(1) - √3
=> 2 - √3
Step-by-step explanation:
I would go with a or b but one sec let me work it out
