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vovangra [49]
2 years ago
5

Explain how low atomspheric oxygen levels affected alligators growth in terms of celluar respiration

Chemistry
1 answer:
Paraphin [41]2 years ago
3 0

Answer:

Answer: Hyperoxic alligators show significantly lower breathing rates than their siblings in normoxic and hypoxic groups. Conversely, each breath supports greater oxygen consumption in hyperoxic animals than in other groups. Statistical significance between groups was calculated by ANOVA with post hoc Tukey-Kramer

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In the presence of a base, blue litmus paper will .<br>O turn purple<br>stay blue<br>to turn red​
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In the presence of a base, blue litmus paper will turn red........

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Hiii please help me to balance the chemical equation:
Fed [463]

Answer:

2Na + 2H2O = 2NaOH + H2

Explanation:

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3 years ago
A solution of sucrose (sugar) in water is in equilibrium with solid sucrose. If more solid sucrose is now added, with stirring,
denis-greek [22]

When equilibrium is reached, the solution is said to be saturated. A solution containing a higher concentration of solute than its solubility is said to be supersaturated.

Answer: d

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2 years ago
2.3 moles of CaBr2 contains how many molecules
kkurt [141]

Avogadro's law states that in every mole of a substance, there are 6.022 \times 10^{23} molecules.

This means that in 2.3 moles, there are 2.3(6.022 \times 10^{23})=\boxed{1.4 \times 10^{24} \text{ (to 2 sf)}}

7 0
1 year ago
The analysis of 2.12 of a compound gave 0.33 of carbon, 1.82 of the same compound gave 1.53 of sulphur. Calculate the emperical
luda_lava [24]

Answer:

CS₂

Explanation:

To find the empirical formula we need to determine first the percentage of each atom in the molecule. Then, we need to find the moles and, as empirical formula is the simplest whole-number ratio of atoms we can solve the empirical formula:

<em>%C:</em>

0.33gC / 2.12g * 100 = 15.6%

<em>%S:</em>

1.53g S / 1.82g * 100 = 84.1%

In a basis of 100, the moles of each atom are:

<em>C:</em>

15.6g C * (1mol / 12.01g) = 1.30 moles

<em>S:</em>

84.1g S * (1mol / 32.065g) = 2.62 moles

The ratio of Sulphur-Carbon is:

2.62mol / 1.30mol = 2

That means empirical formula is:

<h3>CS₂</h3>
6 0
2 years ago
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