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vovangra [49]
2 years ago
5

Explain how low atomspheric oxygen levels affected alligators growth in terms of celluar respiration

Chemistry
1 answer:
Paraphin [41]2 years ago
3 0

Answer:

Answer: Hyperoxic alligators show significantly lower breathing rates than their siblings in normoxic and hypoxic groups. Conversely, each breath supports greater oxygen consumption in hyperoxic animals than in other groups. Statistical significance between groups was calculated by ANOVA with post hoc Tukey-Kramer

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A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )
Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g)   (1)

The reaction rate of equation (1) is given by:

rate = k*[O_{3}][NO]     (2)

<u>We have:</u>

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s  

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

\frac{\Delta[NO_{2}]}{\Delta t} = rate

\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!                                

5 0
2 years ago
How does a sex cell differ from a body cell
Delvig [45]

Sex cells have one set of chromosomes; body cells have two.

I hope this helps you.

5 0
2 years ago
Ldentify the atom whose nucleus is<br> composed of 56 protons and 82<br> neutrons.
kenny6666 [7]

Answer:

Barium-138

Explanation:

The mass number is the atomic number + the number of neutrons. ... Identify the atom whose nucleus is composed of 56 protons and 82 neutrons. Barium-138 (the number of protons identifies the atom) Gallium has two naturally occurring isotopes: Ga-69 with a mass of 68.9256 amu and a natural abundance of 60.11% and Ga-71.

4 0
2 years ago
Determine the number of moles present in 32.5 g aluminum chloride.
Artyom0805 [142]
The number of moles in 32.5g of aluminum chloride is approximately 0.250 moles.
3 0
3 years ago
A 71.0 mL aliquot of a 1.80 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by a
larisa [96]

Answer:

The final concentration is 0.288 M (approximately)

Explanation:

Using dilution formula:

C1V1 = C2V2

Where C1 is the initial concentration

C2 is the final concentration

V1 is the initial volume

V2 is the final volume

In the first dilution, C1 = 1.8M,

V1 =71mL, V2 = 218mL from the formula C2 = 1.8 ×71/281

=0.5862M

In the second dilution,

C1 = 0.5862M, V1 = 109mL, V2 = 222 mL (109+113)

C2 = 0.5862 × 109 ÷ 222

= 0.288 M (approximately) assuming volume is additive.

4 0
2 years ago
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