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Novay_Z [31]
3 years ago
13

RUIGA GIRLS

Chemistry
1 answer:
olga_2 [115]3 years ago
6 0
1)
Common salt= sodium, chlorine
Hydrated copper sulfate= copper, sulfur, water
Sulphuric acid=hydrogen, sulfur, oxygen
2)
Idfk
3)
a)Relative atomic mass is the average mass of an elements atoms(total number of protons and neutrons)
b)An isotope is a form of an element that has the same number of protons but different number of neutrons
c)idfk
Btw ur teachers name is hot
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A substance registers a temperature change from 20 to 40 to what incremental temperature change does this correspond
ss7ja [257]

<u>Given:</u>

Initial temperature, T1 = 20 C

Final temperature, T2 = 40 C

<u>To determine:</u>

The temperature change

<u>Explanation:</u>

Convert degree C to Kelvin

Temperature in Kelvin = degree C + 273

T1 = 20 + 273 = 293 K

T2 = 40 + 273 = 313 K

Incremental temperature change = T2 - T1 = 313-293 = 20 K

Ans: The temperature change in kelvin is 20 K

3 0
2 years ago
Oxidation state of Nitrogen in N2O5​
balandron [24]

Explanation:

Oxidation state of Nitrogen in N2O5 is +5

7 0
1 year ago
What mass, in grams, of sodium sulfate is needed to make 230.5 g of a 3.5 % (m/m) aqueous solution of sodium sulfate?
andreev551 [17]

The percent concentration of a solution can be calculated from; mass of solute /mass of solution * 100. The mass of the solute here is 8.1 g.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute presnt in a solution. There are many ways of expressing concentration such as molarity, molality and percentage.

Here;

mass of solution = 230.5 g

Percent of solute =  3.5 %

3.5 = x/ 230.5 * 100

3.5 = 100x/230.5

230.5(3.5) = 100x

x = 230.5(3.5) /100

x = 8.1 g

Learn more about percent concentration: brainly.com/question/202460?

7 0
1 year ago
Combustibilty defined?
Phantasy [73]
Capable of catching fire
8 0
3 years ago
If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte
Assoli18 [71]

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

6 0
3 years ago
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