This is a hypergeometric distribution problem.
Population (N=50=W+B) is divided into two classes, W (W=20) and B (B=30).
We calculate the probability of choosing w (w=2) white and b (b=5) black marbles.
Hypergeometric probability gives
P(W,B,w,b)=C(W,w)C(B,b)/(C(W+B,w+b)
where
C(n,r)=n!/(r!(n-r)!) the number of combinations of choosing r out of n objects.
Here
P(20,30,2,5)
=C(20,2)C(30,5)/(20+30, 2+5)
=190*142506/99884400
=0.2710
Alternatively, doing the combinatorics way:
#of ways to choose 2 from 20 =C(20,2)
#of ways to choose 5 from 30=C(30,5)
total #of ways = C(50,7)
P(20,30,2,5)=C(20,2)*C(30,5)/C(50,7)
=0.2710
as before.
Answer:
See explanation
Step-by-step explanation:
Given:
18m + 42n
These two variables are not the same, so we can't add the two terms. However, we can factor out a number out of this expression.
The GCF of 18 and 42 is 6.
We can draw 6 out of this expression to get 6(3m + 7n).
This is an equivalent expression.
We can also draw 2 out to get 2(9m + 21n).
We can also draw 3 out to get 3(6m + 14n).
We can also draw 1/2 out to get (1/2)(36m + 84n).
There are endless possibilities, but these are a few. You get the idea!
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<span>Triangles ABC and DEF are similar. The ratio of the side lengths in triangle ABC to triangle DEF is 1:3. If the area of triangle ABC is 1 square unit, what is the area of triangle DEF?
</span>
The part of the proof that uses the justification that angles with a combined degree of 90° are complementary is; Congruent Complements Theorem
<h3>How to prove complementary angles?</h3>
We are given;
m∠1 = 40°
m∠2 = 50°
∠2 is complementary to ∠3
We want to prove that ∠1 ≅ ∠3
Now, when the sum of two angles equals 90°, they are called complementary angles.
Now, looking at the angles, the proof that ∠1 ≅ ∠3 is Congruent Complements Theorem. This is because If two angles are complements of the same angle (or congruent angles), then the two angles are congruent.
Read more about Complementary angles at; brainly.com/question/98924
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