compare the divisor x-3 with x-a which will give a=3 and then use remainder theorem.
The students in Ms. Dodd's class recorded the height in feet of palm trees on school property. Their heights were as follows:
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Answer:
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Step-by-step explanation:
You treat inequality questions just like normal equation with an equal sign. You only have to worry about the inequality when you do the shading part.
Your first goal is to solve for y, which I did at the top.
And remember that when you divide/multiply by a negative number you have to flip the inequality sign.
So the first equation is already in term of y. (y < 2x + 4)
So you only have to solve for y for -3x - 2y ≥ 6.
I solved that and got y ≤ -3/2x - 3.
Now you have 2 equations. y < 2x + 4 and y ≤ -3/2x - 3
First you gotta treat it like a normal equation and graph them.
So i graphed y = 2x + 4 and y = -3/2x - 3. I assume you already know how do do that.
btw. < and > have dotted lines, while ≤ and ≥ have solid lines.
Now for the shading, you gotta look at the inequality sign.
y < 2x + 4 has a less than sign, so you have to shade everything underneath the line you graphed.
y ≤ -3/2x - 3 is also less than, so you have to shade everything underneath that line as well.
So in the future, you you get a > or ≥ then you have to shade above the graph.
