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ICE Princess25 [194]
3 years ago
11

15 pointsss answer pleaseeeeeee fast

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0
Need to think toondjdj
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HELP ME OUT !!! im stressing out keep getting it wrong
Arlecino [84]

Answer:

x=24, y = 33/360 π×24^2/(sin^2(33° (degrees)))

Step-by-step explanation:

notice that x = MK = HM = 24.

Let the center of the circle be C.

Also, notice the radius of the circle can be expressed as the hypotenuse of HMC. Using some trig, we figure out that the radius is 24/sin(33 degrees).

Using the radius of the circle, we can figure out the circumference. The circumference is pi*r^2=(24/sin(33 degrees))^2*pi=pi*24^2/(sin(33 degrees)^2)

Lastly, notice that y = 33/360*circumference = 33/360 π×24^2/(sin^2(33° (degrees)))

hopefully this helped

8 0
3 years ago
Does 0.8 ,3,2.4,and 9 form a proportion​
nasty-shy [4]

Answer:

Yes your numbers can form a proportion

7 0
3 years ago
How do I do this equation for my son 7.32 - 1.909
MrRa [10]

the answer is 5.411.

https://youtu.be/MdthGCQfC0o

this is a link to a video about subtracting decimals simply

7 0
3 years ago
Read 2 more answers
Hi again here's the picture
pshichka [43]

Answer:

<h2>351.88 m</h2>

Step-by-step explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

= 2( \frac{\pi \: d}{2}  + l)

Plug the values

= 2( \frac{3.14  \times 42}{2}  + 110)

Calculate the product

= 2( \frac{131.88}{2}  + 110)

Divide

= 2 (65.94 + 110)

Calculate the sum

= 2 \times 175.94

Calculate

= 351.88 \: m

Hope this helps..

Best regards!!

8 0
3 years ago
Read 2 more answers
The half-life of cesium-137 is 30 years. Suppose we have a
VMariaS [17]
(a) If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) e^{kt}=100e^{kt}.

y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\&#10;y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}

(b) y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}

(c)
100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\&#10;t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}
 
3 0
3 years ago
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