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2 years ago

The ratio of a rectangle's width to length is 3:4. The area of the rectangle is 432 square feet. Find the length and width of

Mathematics

1 answer:

Musya8 [376]2 years ago

8 0

Answer:

36...? After doing all of the incorrect math.. I got 36. Sry if it's wrong.

Step-by-step explanation:

I suck at math. :/

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Joan wants to set a 4-digit unlock code for her mobile phone. She plans to use only odd numbers and to make sure that no number

LuckyWell [14K]

Answer: 120

Step-by-step explanation:

There are 5 digits that are odd, 1 3 5 7 9

There are 5 possibilities for the first digit, 4 for the second, 3 for the third, and 2 for the last, so there are 5 x 4 x 3 x 2 = 120

6 0

10 months ago

6. Find the function with x-intercepts (-3,0) and (5,0), which also goes through the point (1,8)

Yakvenalex [24]

Answer:

f(x) = (-1/2)(x^2 + 8x - 15)

Step-by-step explanation:

This function has two roots: -3 and 5. Most likely it is a quadratic (all of which have two roots).

Then f(x) = a(x + 3)(x - 5)

The graph goes through (1. 8): Therefore, y = 8 when x = 1:

f(1) = a(1 + 3)(1 - 5) = 8, or

a(4)(-4) = 8, or

-16a = 8, which leads to a = -1/2.

Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or

f(x) = (-1/2)(x^2 + 8x - 15)

4 0

2 years ago

13/15 - 1/4 = Please help me

podryga [215]

13/15-1/4

=52/60-15/60

=52-15

______

=37/60

hope it helps..uu frnd

5 0

2 years ago

Read 2 more answers

Help please asap. best answer gets brainliest.

schepotkina [342]

Answer:

Step-by-step explanation:

4 is coefficient

x is variable

12 is constant

5 0

3 years ago

Read 2 more answers

Find the radius of the circle with equation x²+y²+8x+8y+28=0

galina1969 [7]

<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^{2}+y^{2}+8x+8y+28=0$

So, solving we have:

$x^{2}+y^{2}+8x+8y=-28$

$(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4$

$(x^2-(-4))+(y^2-(-4))=4$

Now, we have that:

$h=-4\\k=-4\\r=\sqrt{4}=2$

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0

3 years ago