Answer:
minimum distance will be 13.33 m
Explanation:
We have given the speed of both the car = 80 km/h
We know that 1 km =1000 m
And 1 hour = 60×60 =3600 sec
So
Reaction time is given as t = 0.60 sec
Minimum distance will be equal to the distance driver needed during reaction time
So minimum distance = u ×t =22.22 ×0.60=13.33 m
Answer:
Inner radius = 2 mm
Explanation:
In a coaxial cable, series inductance per unit length is given by the formula;
L' = (µ/(2π))•ln(R/r)
Where R is outer radius and r is inner radius.
We are given;
L' = 50 nH/m = 50 × 10^(-9) H/m
R = 2.6mm = 2.6 × 10^(-3) m
Meanwhile µ is magnetic constant and has a value of µ = µ_o = 4π × 10^(−7) H/m
Plugging in the relevant values, we have;
50 × 10^(-9) = (4π × 10^(−7))/(2π)) × ln(2.6 × 10^(-3)/r)
Rearranging, we have;
(50 × 10^(-9))/(2 × 10^(−7)) = ln((2.6 × 10^(-3))/r)
0.25 = ln((2.6 × 10^(-3))/r)
So,
e^(0.25) = (2.6 × 10^(-3))/r)
1.284 = (2.6 × 10^(-3))/r)
Cross multiply to give;
r = (2.6 × 10^(-3))/1.284)
r = 0.002 m or 2 mm
It's A.Gas molecules moving more quickly..... hope it helps you dear
The phase angle between the voltages of the capacitor and inductor in rlc circuit is 180°.
The phase angle is the component of a periodic wave. It is the shift between the AC current and the voltage on the measured impedance. The two elements of phase angle are reactance(X) and resistance (R).
The phrase for phase angle is, Xₐ = sinωt
where Xₐ= phase angle
ω = wavelength of the wave in 1 revolution
t = time period of 1 revolution
The instantaneous voltage ΔvR is in phase with the current, ΔvL leads the current by 90°, while ΔvC lags behind the current by 90°. The instantaneous values of these three voltages do add algebraically to give the instantaneous voltages across the RLC combination.
Learn more about phase angle here brainly.com/question/14391865
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