All categories

3 years ago

2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure

Physics

1 answer:

egoroff_w [7]3 years ago

7 0

We have,

The mass of sally's mug is 1 kg
The pressure appliedby the mug is 1100 pascal.

We know that,

Pressure = Force/Area

As, we already have the value of pressure, let's calculate that of force now;

F = ma
F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
F = 10 N

Just put all the values in the formula now;

P = F/A
1100 = 10 / A
1100/10 = A
110 m² = A

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

Surface area = Circumference

So, let's solve it;

Circumference = 2πr
110 = 2 × 22/7 × r
110 × 7/2 × 22 = r
5 × 7 = r
35 cm = r

Thus, the radius of the circle is 35 cm.

You might be interested in

A person pulls a bucket of water up from a well with a rope. Assume the initial and final speeds of the bucket are zero (Vi-Vf-0

n200080 [17]

Answer:

This a closed system because the mass of the system is conserved

The energy system that undergoes change is the Potential energy system

The energy system diagram is shown on the first uploaded image

Work done = Change in gravitational potential energy

So solving algebraically for work done would be

Work done = $m*g*h$

where m is mass

g is acceleration due to gravity

and h is the height

Work done in terms of force and distance is = mg

where m is mass of bucket and

g is acceleration due to gravity

Explanation:

a) At the start, potential and kinetic energy were zero. so, energy is zero.

As the person pulls the bucket up, the potential energy becomes mgh.

so,final energy will be consisting of only potential energy.

B) Here work done is equal to change in gravitational potential energy.

W = $\Delta P.E$

W = m*g*h

where g = 9.9 m/ $s^2$

C) Work = force * distance

mgh = force * h

force = mg

force = weight of bucket

6 0

3 years ago

The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s$

6 0

3 years ago

A moving walkway at an airport has a speed v1 and a length L. A woman stands on the walkway as it moves from one end to the othe

bearhunter [10]

Answer:

t=L/ $V_1$

Explanation:

solution:

Let E be an observer, and B a second observer traveling with velocity $V_{BE}$ as measured by E. If E measures the velocity of an object A as $V_{AE}$ then B will measure A velocity as

$V_{AB}$ = $V_{AE}$ - $V_{BE}$

Applied here,

the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is

$V_{MW}$ = $V_{ME}$ - $V_{WE}$

$V_1=V_{WE}$ ,

$V_2=V_{MW}$

The time required for the woman, traveling at constant speed $V_1$ relative to the ground, to travel distance L relative to the ground is :

t=L/ $V_1$

3 0

4 years ago

1. Which of the following equations can be used to directly calculate an object s momentum, p?

Taya2010 [7]

Answer:

p = mv

Explanation:

The momentum of an object is given by the equation:

$p=mv$

where

m is the mass of the object

v is the velocity

Since velocity is a vector, it follows that momentum is a vector as well, therefore it has a magnitude and a direction (the same as the velocity).

The SI unit of the momentum is $kg \cdot m\cdot s^{-1}$

An important law related to the momentum is the law of conservation of momentum, which states that for an isolated system (= zero net external force on it), the total momentum of the system is conserved.

3 0

3 years ago

During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 31.7 rad/s. Find the angular displ

Crank

Answer:

$\Delta \theta = 3116.11\,rad$ and $\Delta \theta = 495.944\,rev$

Explanation:

The tub rotates at constant speed and the kinematic formula to describe the change in angular displacement ( $\Delta \theta$ ), measured in radians, is: