Please help me: Questions are represented on photo above

The diagram represents the truth values of the statements p and q.

Ira Lisetskai [31]

From the given figure, the statement that is true is "<span>The truth value of p ↔ q is 46".

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3 0

3 years ago

Data from an independent research company found that the annual cost per worker for insurance (health, life, liability, etc.)

lesantik [10]

Answer:

The cost per worker goes in five years from $67.81 at 1997, to $394.14 in 2001. It is an increase of $326.33 (481%).

$f(0)=67.81e^{0.44\cdot 0}=67.81*1=67.81\\\\f(1)=67.81e^{0.44\cdot1}=67.81*1.553=105.29\\\\f(2)=67.81e^{0.44\cdot2}=67.81*2.411=163.48\\\\f(3)=67.81e^{0.44\cdot3}=67.81*3.743=253.84\\\\f(4)=67.81e^{0.44\cdot4}=67.81*5.812=394.14\\\\$

Step-by-step explanation:

The annual cost per worker is modeled by the function:

$f(x)=67.81e^{0.44\cdot x}$

where x = years from 1997.

We have to calculate the cost per worker from 1997 to 2001, according to the function f(x).

We have:

$f(0)=67.81e^{0.44\cdot 0}=67.81*1=67.81\\\\f(1)=67.81e^{0.44\cdot1}=67.81*1.553=105.29\\\\f(2)=67.81e^{0.44\cdot2}=67.81*2.411=163.48\\\\f(3)=67.81e^{0.44\cdot3}=67.81*3.743=253.84\\\\f(4)=67.81e^{0.44\cdot4}=67.81*5.812=394.14\\\\$

The cost per worker goes in five years from $67.81 at 1997, to $394.14 in 2001. It is an increase of $326.33 (481%).

5 0

3 years ago

Evaluate 2a + 6b for a = 4 and b = 5.<br>12a+60 =<br>2a + 6b=

galina1969 [7]

Answer:

38 and 108

Step-by-step explanation:

2a + 6b

2 (4) + 6 (5) Plug in values

8+30 = 38

12a + 60

12 (4) + 60 = 108

5 0

3 years ago

Read 2 more answers

Write the equation in standard form for the circle with radius 11 centered at the origin.

MissTica

Answer:

x^2+y^2=121

Step-by-step explanation:

Since you are at (0,0), you don't need to put K or H for the equation (x-h)^2+(y-k)^2=a^2.

8 0

3 years ago

The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b

Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

b) $p_v =P(z>2.32)=0.0102$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

For this case the statistic is given by $z_{calc}= 2.32$

Part b: Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.32)=0.0102$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0

4 years ago