To prevent the crate from slipping, the maximum force that the belt can exert on the crate must be equal to the static friction force.
Ff = 0.5 * 16 * 9.8 = 78.4 N
a = 4.9 m/s^2
If acceleration of the belt exceeds the value determined in the previous question, what is the acceleration of the crate?
In this situation, the kinetic friction force is causing the crate to decelerate. So the net force on the crate is 78.4 N minus the kinetic friction force.
Ff = 0.28 * 16 * 9.8 = 43.904 N
Net force = 78.4 – 43.904 = 34.496 N
To determine the acceleration, divide by the mass of the crate.
a = 34.496 ÷ 16 = 2.156 m/s^2
Velocity increases with speed
The answer is number 2 stomata.
21/12 is equal to 1 3/4 hope this helps!
Answer:
As the warmer air over the equator rises, colder air from the poles rushes toward the equator to take its place. Global winds push air masses around Earth and bring changes in the weather. In the United States, global winds called the prevailing westerlies push air masses from west to east.
Explanation: