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2 years ago

What is an example of convection

2 answers:

8 0

Boiling water.The heat passes from the burner into the pot, heating the water at the bottom. Then, this hot water rises and cooler water moves down to replace it, causing a circular motion.

katrin [286]2 years ago

4 0

Some examples of Convection would be:

1) Boiling a pot of water on the stove
2) using a hot radiator to warm the air in a room
3) using heated air to make a hot-air balloon rise up into the sky

[ Can choose anyone, there are three ]

Hope this helps!

You might be interested in

Helen [10]

Answer:

wavelength decreases and frequency increase

Explanation:

the higher the wavelength the smaller the frequency , the smaller the wavelength the higher the frequency

5 0

2 years ago

Using the equation zeff=z−s and assuming that core electrons contribute 1.00 and valence electrons contribute 0.00 to the screen

DIA [1.3K]

Thank you for posting your question here at brainly. Below is the solution. I hope the answer will help.

Cl^- 1s^2 2s^2p^6 3s^2 3p^6 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 
Zeff = Z-S = 17- 10 =7 
K^+ 1s^2 2s^2p^6 3s^2 3p^6; 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 
Zeff = Z-S = 19- 10 = 9

S = 2 + 6.8 + 2.45 = 11.25
Zeff(Cl^-) = 17 – 11.25 = 5.75 
K^+ 1s^2 2s^2p^6 3s^2 3p^6 same S as for Cl^- but Z increases by 2 hence 
Zeff(K^+) = 19 - 11.25 = 7.75

5 0

3 years ago

Read 2 more answers

A crate lies on a plane tilted at an angle θ = 22.5 ∘ to the horizontal, with μk = 0.19.

ValentinkaMS [17]

A) $2.03 m/s^2$

Let's start by writing the equation of the forces along the directions parallel and perpendicular to the incline:

Parallel:

$mg sin \theta - \mu_k R = ma$ (1)

where

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

$\theta=22.5^{\circ}$

$\mu_k = 0.19$ is the coefficient of friction

R is the normal reaction

a is the acceleration

Perpendicular:

$R-mg cos \theta =0$ (2)

From (2) we find

$R=mg cos \theta$

And substituting into (1)

$mg sin \theta - \mu_k mg cos \theta = ma$

Solving for a,

$a=g sin \theta - \mu_k g cos \theta = (9.8)(sin 22.5)-(0.19)(9.8)(cos 22.5)=2.03 m/s^2$

B) 5.94 m/s

We can solve this part by using the suvat equation

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = ?

u = 0 (it starts from rest)

$a=2.03 m/s^2$

s = 8.70 m

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(2.03)(8.70)}=5.94 m/s$

6 0

3 years ago

Someone plz answrr why is motion important in our lives

sergiy2304 [10]

Answer:

lives, forces and motion make things move and stay still. Pushing and pulling are examples of forces that can sped things up or slow things down. There are two types of forces, at a distance force and contact forces..

5 0

3 years ago

Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section

ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W / ( E × π × P ) ...................1

put here all value

σ = (0.286)² × W × $10^{-16}$ / ( 250 × π × 20 )

1300 × $10^{-24}$ = (0.286)² × W × $10^{-16}$ / ( 250 × π × 20 )

solve it and we get W

W = 249.56 × $10^{-2}$

so elastic partial width is 2.49 eV

8 0

3 years ago