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Agata [3.3K]
3 years ago
6

Which describes the properties reflection, absorption, and transmission when a light is shinning on the oval end of a silver spo

on?
A.
It reflects some light, transmits some light, and absorbs no light.

B.
It reflects a lot of light, transmits almost no light, and absorbs some light.

C.
It reflects all light, transmits all light, and absorbs some light.

D.
It reflects almost no light, transmits almost no light, and absorbs almost no light.
Physics
1 answer:
Trava [24]3 years ago
8 0
The correct answer is C. Hope this helps
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On a rectangle with length 100 m, width 50m and 2 vehicles stationed together. Find the time that they meet given that car A tra
zhannawk [14.2K]

Answer:

T=35.625sec

Explanation:

From the question we are told that:

Length L=100 m

Width W=50m

Velocity of Car A V_A=5m/s

Velocity of Car B V_B=3m/s

Distance traveled by car A before car B moves

d_l=5*3

d_l=15

Therefore total distance traveled at same time interval

D=total\ distance-d_l

Where

Total distance=Perimeter of rectangle

P=2(L+B)

P=2(100+50)

P=300

Therefore

D=total\ distance-d_l

D=300-15\\D=285m

Generally the equation for time taken to meet is mathematically given by

T=\frac{Distance D}{Relative\ speed V_r}

Where

Relative speed = Speed of car A +Speed of car B

V_r=V_A+V_B

V_r=5+3

V_r=8m/s

Therefore the time taken to meet

T=\frac{ D}{ V_r}

T=\frac{ 285}{ 8}

T=35.625sec

8 0
3 years ago
Why are different constellations<br> of stars seen during different<br> seasons?
slamgirl [31]
Actually, they're not.  There's a group of stars and constellations arranged
around the pole of the sky that's visible at any time of any dark, clear night,
all year around.  And any star or constellation in the rest of the sky is visible
for roughly 11 out of every 12 months ... at SOME time of the night. 

Constellations appear to change drastically from one season to the next,
and even from one month to the next, only if you do your stargazing around
the same time every night.

Why does the night sky change at various times of the year ?  Here's how to
think about it:

The Earth spins once a day. You spin along with the Earth, and your clock is
built to follow the sun . "Noon" is the time when the sun is directly over your
head, and "Midnight" is the time when the sun is directly beneath your feet.

Let's say that you go out and look at the stars tonight at midnight, when you're
facing directly away from the sun.

In 6 months from now, when you and the Earth are halfway around on the other
side of the sun, where are those same stars ?  Now they're straight in the
direction of the sun.  So they're directly overhead at Noon, not at Midnight.

THAT's why stars and constellations appear to be in a different part of the sky,
at the same time of night on different dates.
5 0
4 years ago
Read 2 more answers
As a stunt for movie two cars are to collide with each other head on. The two cars are initially 125 apart. Car A is heading str
Tema [17]

Answer:

3.39724 seconds

23.0824792352 m, 101.917520765 m

13.58896 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The equation of motion will be

s=ut+\dfrac{1}{2}at^2\\\Rightarrow 125=30\times t+\dfrac{1}{2}\times 4\times t^2\\\Rightarrow 2t^2+30t-125=0\ m

t=\frac{5\left(\sqrt{19}-3\right)}{2},\:t=-\frac{5\left(3+\sqrt{19}\right)}{2}\\\Rightarrow t=3.39724, -18.39724

The time at which the cars collide is 3.39724 seconds

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 3.39724^2\\\Rightarrow s=23.0824792352\ m

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

v=u+at\\\Rightarrow v=0+4\times 3.39724\\\Rightarrow v=13.58896\ m/s

The speed of car B is 13.58896 m/s

4 0
3 years ago
which of the four terms below includes the other three terms (1)community (2)ecosystem (3)population (4)individuala
Brut [27]
I think the answer is 3, population.
7 0
4 years ago
A balloon is inflated from 0.0100 l to 0.400 l against an external pressure of 10.00 atm. how much work is done in joules? 101.3
Ganezh [65]
To calculate the work, we use:
W = PΔV
W = 10(0.4-0.01)
W = 3.9 L*atm
W = 3.9 * 101.3
W = 395.07 Joules
4 0
4 years ago
Read 2 more answers
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