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3 years ago

True or false

Mathematics

1 answer:

vodomira [7]3 years ago

7 0

4. at least two sides are congruent

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The letters a,b and c, represent nonzero constants. Solve ax+b=c for x

insens350 [35]

Answer:

$x = \frac{c-b}{a}$

Step-by-step explanation:

To solve for x, x needs to be on one side while all the other variables are on the other

To do this first subtract b from each side making the equation,

ax = c - b

Now divide by a on both sides. This means that to solve for x the equation must be ...

$x = \frac{c-b}{a}$

4 0

4 years ago

What is 0.95 × 3.75?

Alborosie

The answer is 3.5625

6 0

3 years ago

Read 2 more answers

Need help badly don’t have answer to this problem.

NikAS [45]

There are a couple of ways to tackle this one, using the 45-45-90 rule or just using the pythagorean theore, let's use the pythagorean theorem.

the angle at A is 45°, and its opposite side is BC, the angle at C is 45° as well, and its opposite side is AB, well, the angles are the same, thus BC = AB.

hmmm le'ts call hmmm ohh hmmm say z, thus BC = AB = z.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2 \implies (6\sqrt{2})^2=z^2+z^2
\qquad 
\begin{cases}
c=\stackrel{6\sqrt{2}}{hypotenuse}\\
a=\stackrel{z}{adjacent}\\
b=\stackrel{z}{opposite}\\
\end{cases}\\\\\\ 6^2(\sqrt{2})^2=2z^2\implies 36(2)=2z^2\implies \cfrac{36(2)}{2}=z^2\implies 36=z^2
\\\\\\
\sqrt{36}=z\implies 6=z$

4 0

4 years ago

Read 2 more answers

Meiko is hanging a picture collage on her wall. The dimensions of the collage are shown in the diagram. She plans to cover

alexira [117]

Answer: $\frac{A_{collage}}{15.75\ in^2}$

Step-by-step explanation:

Since you did not attach the diagram and I don't know the dimensions of the collage, I will give you a general explanation of the procedure you need to use in order to solve the exercise:

1. You need to use the formula for calculate the area of a rectangle:

$A=lw$

Where "l" is the length and "w" is the width.

2. Using the formula, you must calculate the area of an small picture.

You know that its length is 4.5 inches and its width is 3.5 inches. Therefore, its area is:

$A_{picture}=(4.5\ in)(3.5\ in)\\\\A_{picture}=15.75\ in^2$

3. Calculate the area of the collage using the formula:

$A_{collage}=(l_{collage})(w_{collage})$

4. Finally, divide the area of the collage by the area of an small picture in order to find the number of small pictures that will fit within the collage:

$\frac{A_{collage}}{15.75\ in^2}$

5 0

3 years ago

Read 2 more answers

Help. - Math - ^ Photo ^

lesya [120]

Is you do the answer first 725 times 493 it would equal 357,425
then i just did lana first because it was easy and it came out to 357,425
tamir way of solving the problem was wrong equaling 281,815

6 0

3 years ago