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guapka [62]
3 years ago
9

The spine of a science textbook is 0.50 inches. How many science textbooks can be placed standing up on a shelf that is 12 inche

s long?
Justify your answer with models, pictures, and/or equations.
equations.
Spine = width
Mathematics
1 answer:
kramer3 years ago
7 0
24 stared text books
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A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. if th
Oxana [17]
1 revolution of a circle = circumference of that circle.

<span>1 revolution of a circle with the diameter of 28 inches = </span><span><span>πd=28π</span><span>πd=28π</span></span><span> inches. Hence, x revolutions per second = </span><span><span>28πx</span><span>28πx</span></span><span> inches per second = </span><span><span>60∗28πx</span><span>60∗28πx</span></span><span> inches </span>per minute.

<span>Given that </span><span><span>60∗28πx=35πn</span><span>60∗28πx=35πn</span></span><span> --> </span><span><span>n=<span><span>60∗28πx</span><span>35π</span></span>=48x</span><span>n=<span><span>60∗28πx</span><span>35π</span></span>=48x</span></span><span>.</span>
7 0
3 years ago
Hey I’m confused on this problem help.
PilotLPTM [1.2K]

the answer is b carmella

7 0
2 years ago
Parallelogram R S T U is shown. Angle S is 70 degrees.
olya-2409 [2.1K]

Answer:

<h3>B. m∠R = 110°, m∠T = 110°, m∠U = 70°</h3>

Step-by-step explanation:

The opposite angles of the parallelogram are the same.

From the diagram;

<S = <U and <R = <T

Given

<S = 70°

Since <S = <U, hence <U = 70°

Since the sum of angles in a quadrilateral is 360 degrees, hence;

<R+<S+<T+<U = 360

Since <R = <T, then;

<Y+<S+<T+<U = 360

2<T + 70+70 = 360

2<T = 360-140

2<T = 220

<T = 220/2

<T = 110°

Since <T = <R, then < R = 110°

Hence m∠R = 110°, m∠T = 110°, m∠U = 70°. Option B is correct

4 0
3 years ago
Read 2 more answers
What number is 2% of 35
n200080 [17]
The answer is 0.7                     :)
7 0
3 years ago
Read 2 more answers
The mean weight of frozen yogurt cups in an ice cream parlor is 8 oz.Suppose the weight of each cup served is normally distribut
vaieri [72.5K]

Answer:

10.03% probability of getting a cup weighing more than 8.64oz

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 8, \sigma = 0.5

What is the probability of getting a cup weighing more than 8.64oz

This is the 1 subtracted by the pvalue of Z when X = 8.64. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.64 - 8}{0.5}

Z = 1.28

Z = 1.28 has a pvalue of 0.8997

1 - 0.8997 = 0.1003

10.03% probability of getting a cup weighing more than 8.64oz

4 0
3 years ago
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