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guapka [62]
3 years ago
9

The spine of a science textbook is 0.50 inches. How many science textbooks can be placed standing up on a shelf that is 12 inche

s long?
Justify your answer with models, pictures, and/or equations.
equations.
Spine = width
Mathematics
1 answer:
kramer3 years ago
7 0
24 stared text books
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They are called like terms
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Which is a multiple of 5?
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The answer is 15

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Help please!!,,,,,,,,
ipn [44]

Answer:

Question #3: Answer = 31

Step-by-step explanation

• Plug in 3 for x

• Plug in -4 for y

| -3(3)² + 2(-4) | -(3)(-4)

From here, simplify. Don't forget to use PEMDAS!

| -27 +8 | + 12

| -19 | + 12

19 + 12

31

Use this same method to solve for Question #2!

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3 years ago
A jar contains 12 red marbles, 16 blue marbles, and 18 white marbles. Four marbles are chosen
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10.6 all white marbles

Step-by-step explanation:

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8 0
2 years ago
The travel-to-work time for residents in Ventura County is unknown. Assume the population variance is 39. How large should a sam
katen-ka-za [31]

Answer:

A sample size of 128 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.93}{2} = 0.035

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.035 = 0.965, so z = 1.81

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large should a sample be if the margin of error is 1 minute for a 93% confidence interval

We need a sample size of n, which is found when M = 1. We have that \sigma = \sqrt{39}. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.81*\frac{\sqrt{39}}{\sqrt{n}}

\sqrt{n} = 1.81\sqrt{39}

(\sqrt{n})^2 = (1.81\sqrt{39})^2

n = 127.8

Rounding up

A sample size of 128 is needed.

7 0
3 years ago
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