The given conclusion that ABCD is a square is not valid.
Given that, AC⊥BD and AC≅BD.
We need to determine if the given conclusion is valid.
<h3>What are the properties of squares?</h3>
A square is a closed figure with four equal sides and the interior angles of a square are equal to 90°. A square can have a wide range of properties. Some of the important properties of a square are given below.
- A square is a quadrilateral with 4 sides and 4 vertices.
- All four sides of the square are equal to each other.
- The opposite sides of a square are parallel to each other.
- The interior angle of a square at each vertex is 90°.
- The diagonals of a square bisect each other at 90°.
- The length of the diagonals is equal.
Given that, the diagonals of a quadrilateral are perpendicular to each other and the diagonals of a quadrilateral are equal.
Now, from the properties of a square, we understood that the diagonals of a square are perpendicular to each other and the diagonals of a square are equal.
So, the given quadrilateral can be a square. But only with these two properties can not conclude the quadrilateral is a square.
Therefore, the given conclusion that ABCD is a square is not valid.
To learn more about the properties of a square visit:
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Answer:
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x = 2
Step-by-step explanation:
3(x + 1) - 2 = x + 5
3x + 3 - 2 = x + 5
3x + 1 = x + 5
3x - x = 5 - 1
2x = 4
x = 4 / 2
x = 2
Answer:
x=9
Step-by-step explanation:
Plug in 8 for f(x)
8=2x-10
Isolate the x term by moving the 10
18=2x
Isolate the variable
9=x
