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juin [17]
2 years ago
8

How many moles are in 12.9 grams of Fe?

Chemistry
2 answers:
amid [387]2 years ago
6 0

Answer:

0.1677 is the answer

Explanation:

xeze [42]2 years ago
5 0
0.1677 is the answer
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Select the keyword or phrase that will best complete each sentence. must undergo addition because they have easily broken tt bon
STatiana [176]

Alkenes must undergo addition because they have easily broken tt bonds.

Markonikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.

alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.

Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.

In hydroboration, the boron atom bonds to the substituted carbon.

Hydroxides, amines and alcoxides undergo substitution and elimination, but can do so only when the heteroatom is made into a good leaving group.

8 0
3 years ago
Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it.
kakasveta [241]

Answer:

The volume will be 89.6875 ml

Explanation:

So to count this we will use a single proportion.

0.0640 mol - 1000 ml

5.74×10−3 mol - x ml

x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml

6 0
3 years ago
Hii pls help me to balance the equation thanksss​
tiny-mole [99]

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\boxed{\pmb{\color{gold}{\sf{2SO_{2}(g) + O_{2}(g)\dashrightarrow 2SO_{3}(g)}}}}

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

7 0
2 years ago
Read 2 more answers
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
Explain how its electron configuration influences the chemical behavior of an atom.
Llana [10]

More unstable an electron configuration , the more reactive an atom will    become.

How electron configuration influences the chemical behavior of an atom?

This is happen generally, If we look at the Group 1 elements in the periodic table, they are all highly reactive as they have 1 electron in their outermost shells - an unstable configuration in terms of energy.

Also, the noble gases in Group 8 in the periodic table are 'inert' that means they don't react (or more correctly, have an incredibly low reactivity). This is because they have 8 electrons in their outermost shell and thus have no need to acquire or lose electrons to possess a stable electron configuration.

Hence, electron configuration influences the chemical behavior of an atom.

learn more about electronic configuration here :

brainly.com/question/26084288

#SPJ4

6 0
1 year ago
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