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2 years ago

Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19

Chemistry

1 answer:

beks73 [17]2 years ago

3 0

Answer:

E = 3.6×10⁻¹⁹ J

Explanation:

Given data:

Wavelength = 550 nm (550 ×10⁻⁹ nm)

Energy of wave = ?

Solution:

Formula:

E = h c/λ

c = 3×10⁸ m/s

h = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm

E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm

E = 0.036×10⁻¹⁷ J

E = 3.6×10⁻¹⁹ J

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Write a word equation for the combustion of propane???<br> HELP????

frutty [35]

Answer:

1 mole of propane combines with 5 moles of oxygen gas to produce 3 mole of carbon dioxide and 4 moles of water.

Explanation:

The word equation for the combustion of propane can be obtained from the chemical equation;

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

The word equation is therefore:

1 mole of propane combines with 5 moles of oxygen gas to produce 3 mole of carbon dioxide and 4 moles of water.

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3 years ago

What is the gram formula mass of Glycine , NH2CH2COOH

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3 years ago

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andreev551 [17]

Answer:

1.332 meters per second. // 2.664 meters per second.

Explanation:

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3 years ago

How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium

Pepsi [2]

0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as $\text{Pb}^{2+}$ ions. The formula for a nitrate ion is ${\text{NO}_3}^{-}$ . The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each $\text{Pb}^{2+}$ ion in lead nitrate would pair up with two ${\text{NO}_3}^{-}$ ions. The formula for lead nitrate will be $\text{Pb}({\text{NO}_3})_2$ . Each formula unit of lead nitrate will contain one $\text{Pb}^{2+}$ ion and two ${\text{NO}_3}^{-}$ ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as $\text{Cr}^{3+}$ . Similarly, each $\text{Cr}^{3+}$ will pair up with three ${\text{NO}_3}^{-}$ ions. The formula for chromium (III) nitrate will be $\text{Cr}(\text{NO}_3})_3$ . Each formula unit of chromium (III) nitrate will contain one ${\text{NO}_3}^{-}$ ion and three ${\text{NO}_3}^{-}$ ions.

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3 years ago

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musickatia [10]

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3 years ago

Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19​

Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19