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3 years ago

A/1 * B/C =D

Chemistry

1 answer:

Korvikt [17]3 years ago

7 0

Exchange rate is 1.5 guilders for every 2.4 florins

The conversion factor will be

1.5 guilders / 2.4 florins = 2.4 florins / 1.5 guilders = 1

so if we wish to convert 4 guilders to florins we will use following conversion factor

2.4 florins / 1.5 guilders = B / C

D = 4guilders X 2.4 florins / 1.5 guilders = 6.4 florins

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Maybe someone can help me out with this or give me the equation to find mols/liters - thanks to if you can help, here's the ques

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Answer :The correct answers are :

Concentration in one can soup : Table salt = 6.12 $\frac{mol}{L}$

Table sugar = 5.84 $\frac{mol}{L}$

Concentration in one bowl Soup : Table salt = 3.82 $\frac{mol}{L}$

Table sugar = 3.65 $\frac{mol}{L}$

Concentration : It is quantity to measure a solution . It can be defined as abundance of constituents per volume of solution . The most used concentration is molar concentration .

Molar concentration is defined as mole of solute present in volume of solution . The unit of concentration is $\frac{mol}{L}$ . It is expressed as :

$Concentration ( \frac{mol}{L} ) = \frac{mole of solute (mol)}{Volume of solution (L)}$

Concentration in one can of soup (Volume = 250 mL )

Volume of one can soup = 250 mL . Converting it from mL to L as :

(1 L = 1000mL)

$Volume of one can soup = \frac{250 mL}{1000mL} * 1 L = 0.250 L$

A) Concentration of table salt :

Following are the steps to find out molar concentration :

Step 1 : Find mass of solute :

Since mass of solute is not given , so we take solubility of NaCL in 1 L of water . Solubility is maximum amount of NaCL that can be dissolved in 1 L water at room temperature . From image , we can say that 359 g of NaCL can be dissolved ideally in 1 L of water .

Since volume of solution is 0.250 L , so mass of salt in 0.250 L can be found :

Mass of NaCL in 1 L = 359 g

Mass of NaCL in 0.250 L of water = 359 g * 0.250 L

Mass of NaCL in 0.250 L = 89.75 g

Step 2 : Convert mass of solute to its mole

Mole can be calculate from mass as :

$Mole (mol) = \frac{given mass (g) }{molar mass \frac{g}{mol}}$

Molar mass of Table salt (given ) = 58.44 $\frac{g}{mol}$

plugging value of mass and molar mass in mole formula :

$Mole = \frac{89.75 g }{58.44 \frac{g}{mol}}$

Mole of Table salt = 1.53 mol

Step 3 : To find concentration .

Mole of solute = 1.53 mol

Volume of solution ( one can of soup ) = 0.250 L

Plugging these values in Concentration formula :

$Concentration = \frac{1.53 mol}{0.250 L}$

Concentration of Table salt in one can soup = 6.12 $\frac{mol}{L}$

B) Concentration of Table sugar :

Following steps can be used :

Step 1: To find mass of Table sugar

Since mass of sugar is not given , so solubility of sugar will be considered . From image solubility is 2000 g in 1 L of water .

Since volume of one cup soup is 0.250 L , so mass of Sugar in 0.250 L of solution =

Mass of sugar in 1 L of water = 2000 g

Mass of sugar in 0.250 L of solution = 2000 g* 0.250 L

Hence , mass of Sugar in 0.250 L of solution = 500 g

Step 2 : To convert mass of sugar to its mole

Mass can be converted to mole using same formula. Plugging value in mole formula :

$Mole of sugar = \frac{500 g}{342.3 \frac{g}{mol}}$

Mole of sugar = 1.46 mol

Step 3 : To find concentration of Sugar :

Mole of sugar = 1.46 mol

Volume of solution = 0.250 L

Plugging these values in concentration formula :

$Concentration = \frac{1.46 mol}{0.250 L} = 5.84 \frac{mol}{L}$

-----------------------------------------------------------------------------------------------------------

Concentration in one bowl of soup :

Volume of one bowl of soup = 150 mL water + 250 mL of one can soup

= 400 mL

Converting mL to L : ( 1 L = 1000mL )

$Volume of solution = \frac{400 mL}{1000mL} * 1 L$

Volume of solution = 0.400 L

A) Concentration of Table salt :

Similar steps will be used :

Step 1: T find mass of Table salt

Again solubility will be used , which is =359 g in 1 L .Since 150 mL water is added which had no salt . hence all the salt was present in 250 mL one can soup , so mass of salt present in one can soup will be used .

Mass of Table salt = 89.75 g

Step 2: To convert mass to mole

Mass can be converted using mole formula .

Mole of Table salt = 1.53 mol ( calculated above )

Step 3: To find concentration

Mole of Table salt = 1.53 mol

Volume of one bowl soup = 0.400 L

Plugging these values in Concentration formula as:

$Concentration = \frac{1.53 mol}{0.400 L }$

Concentration of Table salt in one bowl soup = 3.82 $\frac{mol}{L}$

B) Concentration of Table sugar :

Step 1 : To find mass of Table sugar

Mass of sugar in 0.400 L will be same as that of mass of sugar present in 0.250 L since water had no sugar .

Mass of Table sugar = 500 g

Step 2 : To convert mass to mole

Mole can be calculated using mole formula ( as calculated above for one can soup )

Mole of Table sugar = 1.46 mol

Step 3: To find concentration

Mole of Table sugar (solute ) = 1.46 mol

Volume of one bowl soup = 0.400 L

Plugging these values in concentration formula :

$Concentration = \frac{1.46 mol}{0.400 L}$

Concentration of Table sugar in one bowl soup = 3.65 $\frac{mol}{L}$

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Also Note :You have marked Table sugar as Ionic which is incorrect .Table sugar is covalent as it has all non metals .

8 0

4 years ago