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aev [14]
3 years ago
12

Find the midpoint between these points. (1,3) (5.1) someone please help asap !!!

Mathematics
2 answers:
grin007 [14]3 years ago
7 0

Answer:SOLUTION

The midpoint for two points P=(px,py) and Q=(qx,qy) is M=(px+qx2,py+qy2).

We have that px=1, py=3, qx=5, qy=1.

Thus, M=(1+52,3+12)=(3,2).

ANSWER

M=(3,2)A

Step-by-step explanation:

Zarrin [17]3 years ago
4 0

Answer:

The midpoint is (3, 2)

Step-by-step explanation:

To find the x-coordinate of the midpoint, average the x-coordinates 1 and 5:

          1 + 5

xm = ----------- = 3

              2

y-coordinate:

          1 + 3

ym = ----------- = 2

              2

The midpoint is (3, 2)

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----  =  -----  cross multiply

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/36    /36

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or

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3 years ago
Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree h
stepan [7]

Answer:   c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

=0.539\times100=53.9\text{ cm}   [∵ 1 m = 100 cm]             (1)

The circumference of the ash tree= 0.509 yards

=0.509\times3\text{ feet}   [∵ 1 yard = 3 feet]

=0.509\times3\times 30.48\text{ cm}  [∵ 1 foot = 30.48 cm]

=46.54296\approx46.54\text{ cm}        (2)

The circumference of the elm tree = 6281.70 millimeters

=\dfrac{6281.70}{10}=628.17\text{ cm}          (3)

The circumference of the poplar tree = 0.000385 miles

=0.000385 \times5280\text{ feet}   [∵ 1 mile = 5280 feet]

=0.000385 \times5280\times30.48\text{ feet}  [∵ 1 foot = 30.48 cm]

=61.959744\approx61.96\ \text{ cm}              (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

Hence, the elm tree has the greatest circumference.

5 0
3 years ago
Please help me if you can. Please also write how you got the answer thank you.
adelina 88 [10]

Answer:

1) r, q, s. 2). 5

Step-by-step explanation:

1) from the given (q) is smaller than (r) and (s) is less than (q) by 2.

2) you need to make all the fractions have the same numerator so you will multiply both the firs and third fraction by 3÷3 ( which is 1 and will not affect the value but will make the numerator of the fractions equal) and the fractions between them is the second fraction and it's denominator is x and there is 5 fractions between the two numbers so there are 5 possible values of x

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