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3 years ago

HI WANNA BE FRIENDS :)

Chemistry

2 answers:

o-na [289]3 years ago

8 0

Answer:

hiiiiii sureeeeeeee

Naya [18.7K]3 years ago

5 0

Answer:

I don't know. Do you have a steady job and a good house?

No, no, no, I'm just joking. Sure!

Explanation:

You might be interested in

Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?

Lena [83]

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

4 0

3 years ago

Acid + base —> salt + water What type of reaction is this?

erastova [34]

$\sf{Acid}+\bf{Base}\longrightarrow \tt{Salt}+\bold{Water }$

These type of reaction is called as Neutralization Reaction.

8 0

3 years ago

What is the molarity of a solution that contains 12 moles of solute and 583 ml of solution?

frozen [14]

Answer:

21 M

Explanation:

Molarity = mol solute/ L solution = 12 mol/0.583 L ≈ 21 mol/L = 21 M

5 0

3 years ago

If you digested 25 mg of pure ferrocene in nitric acid and then diluted the resulting solution up to 500 mL with 1% aqueous hydr

Vilka [71]

Answer:

1.345*10⁻⁴ mol/L

15.023 mg/L

Explanation:

The chemical formula of ferrocene is Fe(C₅H₅)₂, thus its molecular weight is:

55.845 g/mol + 10*12g/mol + 10 *1g/mol = 185.845 g/mol

The moles of Fe contained in 25 mg (or 0.025 g) of ferrocene are:

$0.025gFerrocene*\frac{1molFerrocene}{185.845g} *\frac{1mol Fe}{1molFerrocene}=1.345*10^{-4} molFe$

The final volume is 500 mL, or 0.5 L. So the iron concentration in mol/L is:

$\frac{1.345*10^{-4}molFe}{0.5L}= 2.69*10^{-4} mol/L$

We can convert that value into mg/L:

$2.69*10^{-4} \frac{molFe}{L} *\frac{55.845g}{1molFe}*\frac{1000mg}{1g}=15.023 mg/L$

6 0

4 years ago

What is the empirical formula for a compound that has 57.5%

Rainbow [258]

Answer:

Explanation:

use %composition given to calculate emperical 4mular

8 0

3 years ago