All categories

3 years ago

Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?

Chemistry

1 answer:

Lena [83]3 years ago

4 0

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

You might be interested in

What is the mole ratio of AlCl3 to AlSO4 in the above chemical reaction?

PSYCHO15rus [73]

What reaction is it?

7 0

3 years ago

Classify these compounds by whether they behave as strong acids, weak acids, strong bases, or weak bases in aqueous solution.

zaharov [31]

Answer:

HI& HNO3= strong acid

H2CO3 &HF= weak acid

LiOH & Ba(OH)2= strong base

CH3NH2= weak base

NH4Cl = weak acid solution

Na3PO4 = weak base solution

Explanation:

HI& HNO3= strong acid because they can dissociate completely producing free Oxonium ions

H2CO3 &HF= weak acid because there dissociate partly in Solution

LiOH & Ba(OH)2= strong base because LiOH is a group one alkali which dissociate completely and Ba(OH)2 a group 2 alkali which dissociate completely as well

CH3NH2= weak base because in solution it dissociates partly forming NH4+ ion

NH4Cl = weak acid solution because it is a salt of strong acid and weak base

Na3PO4 = weak base solution

Because it's a salt of strong base and weak acid

8 0

3 years ago

boron has two naturally occurring isotopes: boron -10 (abundance = 19.8% , mass = 10.013 amu) boron -11 (abundance = 80.2%, mass

Mariulka [41]

Explanation:

eam=%abudance×mass+%abudance×mass

eam=19.8%×10.013/100+80.2%×11.009/100

eam=198.2574/100+882.9218/100

eam=1081.1792/100

eam=10.811792

eam=10.812

6 0

4 years ago

5. A sample of an unknown metal has a mass of 120.4 g. As the sample cools from 90.5°C to 25.7°C, it releases 7020. J of energy.

xxTIMURxx [149]

Answer: The specific heat capacity of the sample is $0.899 J/g^{o}C$ and as heat is released in this reaction so it is exothermic in nature.

Explanation:

Given: Mass = 120.4 g

Heat energy released = -7020 J

Initial temperature = $90.5^{o}C$

Final temperature = $25.7^{o}C$

Formula used is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass of substance

C = specific heat capacity

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\-7020 J = 120.4 g \times C \times (90.5 - 25.7)^{o}C\\C = \frac{-7020 J}{120.4 \times (-64.8^{o}C)}\\= \frac{7020 J}{7801.92} J/g^{o}C\\= 0.899 J/g^{o}C$

When heat is released in a process or reaction then it means it is exothermic in nature.

Thus, we can conclude that the specific heat capacity of the sample is $0.899 J/g^{o}C$ and as heat is released in this reaction so it is exothermic in nature.

5 0

3 years ago

Winds in our atmosphere are created as as result of which of the following processes?

iVinArrow [24]

Answer:

Uneven heating of the air in the atmosphere

hope this helps!

4 0

3 years ago

Read 2 more answers