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3 years ago

Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?

Chemistry

1 answer:

Lena [83]3 years ago

4 0

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

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Please help me. I need help

Doss [256]

Answer:

they both collided is one i guess

Explanation:

5 0

3 years ago

Read 2 more answers

Calculate the number of moles of sodium carbonate originally present, if 6.0 ml of 0.100 M HCl were used to titrate the mixture

valina [46]

Answer:

0.0006 mole

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For HCl :

Molarity = 0.100 M

Volume = 6.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.0×10⁻³ L

Thus, moles of potassium iodide :

$Moles=0.100 \times {6.0\times 10^{-3}}\ moles$

Moles of HCl = 0.0006 moles

From the reaction shown below:-

$HCl+Na_2CO_3\rightarrow NaHCO_3+NaCl$

1 mole of HCl reacts with 1 mole of sodium carbonate.

So,

0.0006 mole of HCl reacts with 0.0006 mole of sodium carbonate.

<u>Moles of sodium carbonate = 0.0006 moles</u>

5 0

3 years ago

Which of the following is the closest to the observed abundance of 71Ga, one of two stable gallium isotopes (69Ga and 71Ga). The

natali 33 [55]

The outcome of that will be 44

3 0

3 years ago

Which solute, an electrolyte or a nonelectrolyte, has the greater effect on the boiling point when a given amount of each

m_a_m_a [10]

Answer:

Electrolyte

Explanation:

The electrolyte does because it dissociates into ions.

5 0

3 years ago

Read 2 more answers

_Cuo +H, → _Cu + _H,0

Elena-2011 [213]

<h3>Answer:</h3>

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

<h3>Explanation:</h3>

Assuming the reaction is the reduction of CuO by H₂
Then the balanced equation for the reaction is;

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.

In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.

3 0

3 years ago