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3 years ago

Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?

Chemistry

1 answer:

Lena [83]3 years ago

4 0

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

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The volume of a single rhodium atom is 1.01×10-23 cm3. What is the volume of a rhodium atom in microliters?

Anni [7]

Answer: 1.01 x 10^20 microliters.

Explanation: volume is defined as a three-dimensional measure of space that comprises a length, a width and a height. In other words, we are asked to convert from one volumetric measure to another (cubic centimeters to microliters) —volume is measured in units of cubic centimeters in metric, cubic inches or cubic feet in English measurement.

If, 1 cm³ = 1000 uL (microliters) then,

1 uL - - - - - - - - - 0.001 cm³ = 1 x 10^-3 cm

x uL - - - - - - - - - 1.01×10^-23 cm³

Therefore,

x uL = 1.01 x 10^-23 cm³ / 0.001 cm³

x uL = 1.01 x 10^(-23 - - 3)

x uL = 1.01 x 10^( - 23 + 3)

x uL = 1.01 x 10^20

Which is to say that a single rhodium atom of volume 1.01 x 10^23 cm³ would occupy 1.01 x 10^20 microliters.

4 0

3 years ago

Sodium phosphate is added to a solution that contains 0.0030 M aluminum nitrate and 0.016 M calcium chloride. The concentration

gavmur [86]

Explanation:

It is given that aluminium nitrate and calcium chloride are mixed together with sodium phosphate.

And, $K_{sp} of AlPO_{4} = 9.84 \times 10^{-21}$

$K_{sp} of Ca_{3}(PO_{4})_{2} = 2.0 \times 10^{-29}$

Let us assume that the solubility be "s". And, the reaction equation is as follows.

$AlPO_{4} \rightleftharpoons Al^{3+} + PO^{3-}_{4}$

$9.84 \times 10^{-21} = s \times s$

s = $9.92 \times 10^{-11}$

Also, $Ca_{3}(PO_{4})_{2} \rightleftharpoons 3Ca^{2+} + 2PO^{3-}_{4}$

$2 \times 10^{-29} = (3s)^{3} \times (2s)^{2}$

s = $7.14 \times 10^{-7}$

This means that first, aluminium phosphate will precipitate.

Now, we will calculate the concentration of phosphate when calcium phosphate starts to precipitate out using the $K_{sp}$ expression as follows.

$K_{sp} = [Ca^{2+}]^{3}[PO^{3-}_{4}]^{2}$

$2.0 \times 10^{-29} = (0.016)^{3}[PO^{3-}_{4}]^{2}$

$2.0 \times 10^{-29} = 4.096 \times 10^{-6} \times [PO^{3-}_{4}]^{2}$

$[PO^{3-}_{4}]^{2}$ = $4.88 \times 10^{-24}$

= $2.21 \times 10^{-12}$ M

Similarly, calculate the concentration of aluminium at this concentration of phosphate as follows.

$AlPO_{4} \rightleftharpoons Al^{3+} + PO^{3-}_{4}$

$K_{sp} = [Al^{3+}][PO^{3-}_{4}]$

$9.84 \times 10^{-21} = [Al^{3+}] \times 2.21 \times 10^{-12}$

$[Al^{3+}] = 4.45 \times 10^{-9}$ M

Thus, we can conclude that concentration of aluminium will be $4.45 \times 10^{-9}$ M when calcium begins to precipitate.

7 0

3 years ago

If a balloon is heated, what happens to the volume of the air in the balloon if the pressure is constant?

MakcuM [25]

Answer:

B. It increases.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

It is clear that, at constant P, the volume of the gas (V) is directly proportional to the temperature of the gas.

V ∝ T.

So, If a balloon is heated, the volume of the air in the balloon if the pressure is constant:

B. It increases.

4 0

3 years ago

When table salt (NaCl) is dissolved into water, it breaks into 2 ions, Na+ and Cl-. The water molecules are attracted to them be

eimsori [14]

Answer:

Explanation:

According to Coulomb's Law, like charges repel each other, whereas unlike charges attract each other. This applies to all charged particles.

When NaCl dissociates into its ions in water, we observe the following ions in the system:

Na+ (positive)

Cl - (negative)

H+ (positive)

OH- (negative)

The only correct option is A where the negatively charged oxygen atoms are attracted to the positively charged sodium atoms.

In option B the charge of the oxygen atom is incorrectly mentioned as positive. In option C, the charge of hydrogen atoms is incorrectly mentioned as negative, and in option D the charges of the atoms are correct, but the pairing is incorrect as like charges repel each other.

<h3>Hope this helps</h3>

3 0

3 years ago

How are models related to theories and hypotheses

Mazyrski [523]

Models are related to theories and hypothesis because the model itself is a representation of what the theories and hypothesis could, would , or should look like.

7 0

3 years ago