Question: Find acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N, If the mass of the refrigerator is 10 kg.
Answer:
40 m/s²
Explanation:
Applying,
F = ma................Equation 1
Where F = Force applied to the refrigerator, m = mass of the refrigerator, a = acceleration of the refrigerator.
make a the subject of the equation
a = F/m............ Equation 2
From the question,
Given: F = 400 N, m = 10 kg
Substitute these values into equation 2
a = 400/10
a = 40 m/s²
Answer:
C)The Same
Explanation:
Kinematics equation:
for both cases the initial velocity in the axis Y is the same, equal a zero.
So the relation between the height ant temps is the same for both cases (the horizontal velocity does not play a role)
C)The Same
Answer: a. -720m/s^2
b. Yes, airbags will deploy
Explanation:
The formula for acceleration is:
= (Final velocity - Initial velocity)/Time
Final velocity = 0m/s
Initial velocity = 36m/s
Time taken = 0.05s
= (Final velocity - Initial velocity)/Time
= (0 - 36)/0.05
= -36/0.05
= -720m/s^2.
Since it's negative, it shows that there was a deceleration.
2. Yes the airbag will deploy since the acceleration gotten is more than -600 m/s^2.
<h2>
Answer: Prism</h2>
In the eighteenth century Isaac Newton found out that <u>when a beam of light from the Sun, passes trhough a prism is decomposed in many different colors</u>. He named this phenomenom as dispersion of light.
This phenomenom occurs when a beam of white light (which is compound of many wavelengths or "colors") is refracted (the different rays of light are diverted depending on their wavelengths) in some medium, leaving their constituent colors separated.
Therefore:
<h2>Isaac Newton used a <u>prism</u> to break white light into its component colors.</h2>
Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.
