Answer:
19m/s
22.3 degrees
Explanation:
it is a case aof relative velocity.
the basic for relative velocity vector equation is :
V_b = V_j + V_(b/j)---------------1
V_b: ball velocity relative to ground
V_j : Jaun velocity relative to ground
V_(b/j): ball velocity relative to jaun
<u>reference frame:</u>
<u>We take east and north as +ve x and +ve y </u>
V_(b/j) = V_b - V_j
so for x-axis;
net x-component of V_(b/j) = 12 sin (37) + 0 = 7.22m/s
net y-component of V_(b/j) = 12 cos (37) + 8 = 17.6m/s
magnitude = ((7.22^2)+(17.6^2))^(0.5) = 19 m/s
<em>*direction with respect to Jaun = angle between the vertical (North) and vector </em>V_(b/j)
<em><u>angle = arctan(7.22/17.6) = 22.3 degrees</u></em>
Answer:
I don't knowI think it will break
Answer:
450000 kg m/s
Explanation:
convert 108km/h to m/s
1km=100m
1h=(60×60)s = 3600s
108km/h= (108×1000)÷3600
=30m/s
K.E =1/2mv^2
=1/2(1×10^3)(30^2)
= 1/2 × 1000 × 900
= 450000 kg m/s
this should be your answer, hope I was able to help.
Answer:
The mean distance of Earth from the Sun is 149.6 × 10^6 km and the mean distance of Mercury from the Sun is 57.9 × 10^6 km.
hope it helps you
Represented elements not discovered in this time