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Advocard [28]
3 years ago
8

An airplane is traveling at a speed of 200 m/s relative to the Earth. A person walks toward the front of the plane at a speed of

1 m/s. How fast is that person traveling in reference to the other people on the plane?
Physics
1 answer:
pochemuha3 years ago
6 0

Answer:

1 m/s

Explanation:

This is because, everybody in the plane including the person walking is moving at the speed of the plane which is 200 m/s. Now, when the person starts to walk with a speed of 1 m/s, his relative velocity to the other passengers is 1 m/s since he is already moving at the speed of the plane before starting to walk.

His velocity relative to the ground V' = velocity of plane relative to ground, V + velocity of person relative to plane, v

V = 200 m/s and v = 1 m/s

So, V' = 200 m/s + 1 m/s = 201 m/s

Since the velocity of the other passengers is the velocity of the plane, V = 200 m/s. The velocity of the person traveling in reference to the other people on the plane is V" = V' - V = 201 m/s - 200 m/s = 1 m/s

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A high speed train is traveling at a speed of 44.7 m/s when the engineer sounds the 415 Hz warning horn. The speed of sound is 3
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Answer:

Explanation:

Speed of the source of sound = v = 44.7 m/s

Speed of sound = V = 343 m/s

a) Apparent  frequency as the train approaches = f =  [V /(V -v) ] × f

= [343 / (343 - 44.7) ] × 415  = 477.18 Hz

Wave length =  λ = v / f = 343 / 477.18 = 0.719 m

b) Frequency heard as the train leaves = f ' =  [V / ( V + v) ] f

                                                                     = [343 / { 343 + 44.7 ) ] x 415

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Wavelength when leaving = v / f = 343 / 367.2 = 0.934 m

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4 years ago
Boron coated with SiC (or Borsic) reinforced aluminum containing aligned 20 vol% fibers is an important high-temperature, lightw
Scilla [17]

Answer:

Option C is correct.

Modulus of elasticity of the composite perpendicular to the fibers = (12 × 10⁶) psi

Explanation:

For combination of materials, the properties (especially physical properties) of the resulting composite is a sum of the fractional contribution of each material thay makes up the composite.

In this composite,

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But modulus of elasticity of the composite perpendicular to the fibers is given in the expression.

[1 ÷ E(perpendicular)]

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[1 ÷ E(perpendicular)]

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= (8.3636 × 10⁻⁸)

E(perpendicular) = 1 ÷ (8.3636 × 10⁻⁸)

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= (12 × 10⁶) psi

Hope this Helps!!!

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dalvyx [7]

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