Answer:
y = 1
Step-by-step explanation:
To find the Horizontal Asymptote, you have to look at the degree of the numerator and denominator.
The right triangle is assumed to be inscribed in the rectangle, such that
hypotenuse is the diagonal of the rectangle.
Reasons:
Let <em>x</em> and<em> </em><em>y</em> represent the length of the sides of the rectangle
Whereby the base and height of the right triangle are the same as the
length and width of the rectangle, we have;
Perimeter of the rectangle = 2·x + 2·y = 68
Therefore;
x + y = 34
The base of the right triangle = x
The height of the right triangle = y
By Pythagoras's theorem, the length of the hypotenuse side = √(x² + y²)
Therefore; Perimeter of the right triangle = x + y + √(x² + y²) = 60
Which gives;
∴√(x² + y²) = 60 - (x + y) = 60 - 34 = 26
The length of the hypotenuse side, √(x² + y²) = <u>26 cm</u>
Learn more about Pythagoras's theorem here:
6 cats/kittens were adopted.
Step-by-step explanation:
Given,
Number of cats/kittens at the event = 44
Number of cats/kittens adopted = x
Number of cats/kittens returned = Twice returned as adopted = 2x
New total = 50
We will subtract the adopted and add the returned cats/kittens.
Total cats/kittens at event - adopted + returned = New total
6 cats/kittens were adopted.
Keywords: expression, variables
Learn more about variables at:
#LearnwithBrainly
Answer:
sum is 125,500
sum in summation notation is = (2a+(n-1)d)n/2
Step-by-step explanation:
This problem can be solved using concept of arithmetic progression.
The sum of n term terms in arithmetic progression is given by
sum = (2a+(n-1)d)n/2
where
a is the first term
d is the common difference of arithmetic progression
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in the problem
series is multiple of 4 starting from 4 ending at 1000
so series will look like
series: 0,4,8,12,16..................1000
a is first term so
here a is 0
lets find d the common difference
common difference is given by nth term - (n-1)th term
lets take nth term as 8
so (n-1)th term = 4
Thus,
d = 8-4 = 4
d can also be seen 4 intuitively as series is multiple of four.
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let calculate value of n
we have last term as 1000
Nth term can be described
Nth term = 0+(n-1)d
1000 = (n-1)4
=> 1000 = 4n -4
=> 1000 + 4= 4n
=> n = 1004/4 = 251
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now we have
n = 1000
a = 0
d = 4
so we can calculate sum of the series by using formula given above
sum = (2a+(n-1)d)n/2
= (2*0 + (251-1)4)251/2
= (250*4)251/2
= 1000*251/2 = 500*251 = 125,500
Thus, sum is 125,500
sum in summation notation is = (2a+(n-1)d)n/2