Yes, it is.
(31√5) / √65=31√(5/65)
Answer: yes, it is.
Answer: Terry should buy the half-liter of water that costs $2.11 because buying 200 litres here is cheaper.
Step-by-step explanation:
Terry is buying water and needs 22 liters. A half-liter of water costs $2.11. Using this information, 22 litres will cost:
= 22 ÷ 1/2 × 2.11
= 22 × 2 × 2.11
= $92.84
Also, A 200 -milliliter container of water costs $1.01. Using this information, 22 litres will cost:
= 22 × 1.01 ÷ 200/1000
= 22 × 1.01 × 1000/200
= 22 × 1.01 × 5
= $111.1
Based on this information, Terry should buy the half-liter of water that costs $2.11 because buying 200 litres here is cheaper.
X + 2 < -4
x < -4 -2
•x < -6
Answer:
41°
Step-by-step explanation:
the sum of the interior angles is 180 degree
so,
38 + x + 101 = 180
139 +x = 180
x = 180 - 139
x= 41°
Answer:
a. 25.98i - 15j mi/h
b. 1.71i + 4.7j mi/h
c. 27.69i -10.3j mi/h
Step-by-step explanation:
a. Identify the ship's vector
Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h
Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h
b. Identify the water current's vector
Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h
Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h
c. Identify the vector representing the ship's actual motion.
The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.
V = v + v'
= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h
= (25.98i + 1.71i + 4.7j - 15j )mi/h
= 27.68i -10.3j mi/h
