Answer:
First part:
Set h(t) = 231and solve for t.
-16t²+ 152t + 9= 231
-16t² + 152t - 222= 0
Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 231 on the way up, and the higher value is the time to reach 231 again, on the way down.
Second part:
Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.
Answer:
(B) 18.
Step-by-step explanation:
We are asked to find the perimeter of a quadrilateral with vertices at (-1, 4), (7,4), (7,5), and (-1. 5).
First of all, we will draw vertices of quadrilateral on coordinate plane and connect the vertices as shown in the attached photo.
We can see that our quadrilateral is a parallelogram, whose parallel sides are equal.
Therefore, the perimeter of the given quadrilateral is 18 units.
D. X = 8 , Y = 6
3x - 14 = x + 23x - x = 2 + 142x = 162x / 2 = 16/2x = 8
To check: 3x - 14 = x + 2 ; 3(8) - 14 = 8 + 2 ; 24 - 14 = 10 ; 10 = 10
4y - 7 = y + 114y - y = 11 + 73y = 183y / 3 = 18 / 3y = 6
To check: 4y - 7 = y + 11 ; 4(6) - 7 = 6 + 11 ; 24 - 7 = 17 ; 17 = 17
hopes it helps:)
<span>Abstract algebra is the set of advanced topics of algebra that deal with abstract algebraic structures rather than the usual number systems.</span>
