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Andrei [34K]
3 years ago
8

Gregory’s backpack weighs 3 pounds less than Cali’s backpack. Cali’s backpack weighs 14 pounds. How much does Gregory’s backpack

weigh?
1. x-3=14
2. 3x=14
3. x=14-3
4. x=14 divided by 3
Mathematics
2 answers:
Elden [556K]3 years ago
7 0

Answer:

3. or 2.

Step-by-step explanation:

Anna [14]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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bekas [8.4K]

Answer:

\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

Step-by-step explanation:

Given

\dfrac{-2}{3} \div 2\dfrac{1}{4} =

Required

Solve

Start by converting the mixed number to improper fraction

\dfrac{-2}{3} \div \dfrac{9}{4} =

Convert the division to muliplication

\dfrac{-2}{3} * \dfrac{4}{9} =

\dfrac{-2*4}{3*9}=

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\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

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3 years ago
Determine the kinetic energy of 8000 Newton’s roller coaster car that is moving with a speed of 20.0 meters/seconds
ohaa [14]

Answer:

The kinetic energy of the roller coaster is 1600000 J.

Step-by-step explanation:

Given:

Mass of the roller coaster is 8000 Newton's and speed 20.0 meters/seconds.

Now, we need to find the kinetic energy E_{k} of the roller coaster.

So, Mass of roller coaster (m) = 8000 N.

Velocity of roller coaster (v) = 20.0 m/s.

Now, putting the formula of kinetic energy:

E_{k} = \frac{1}{2}\times m\times v^{2}

E_{k}=\frac{1}{2} \times 8000\times 20^{2}

E_{k}=\frac{1}{2} \times 8000\times 400

E_{k}=\frac{1}{2} \times 3200000

E_{k}=1600000

Therefore, the kinetic energy of the roller coaster is 1600000 J.

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