Answer: 51.4 g of NaClO will be produced.
Explanation:
To calculate the moles :
According to stoichiometry :
1 moles of require = 2 moles of
Thus 0.69 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.69 moles of give = of
Mass of
Thus 51.4 g of NaClO will be produced
Answer:
You have to add many things
Explanation:
for example u can add why and how also what ur point is
Answer:
130 Liters
Explanation:
if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)
1 moles of any molecules has 6.022 x 10^23 molecules in it
Answer:
the mass = The same
the charge = Neutron has 0, Proton has +1