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Anastasy [175]
1 year ago
10

How many milliliters of a 9.0 h 2so 4 solution are needed to make 0.45 l of a 3.5 m solution?

Chemistry
1 answer:
muminat1 year ago
4 0

To have 175ml is needed of a 9.0M H_{2} SO_{4} solution are needed to make 0.45 L of a 3.5 M (Morality).

<h3>How to calculate the molarity to make the solution?</h3>

The Morality unit (M) is $ \frac{\text { moles of solute }}{\text { liters of solution }}=\mathrm{mol} / \mathrm{L} $

The volume of a solution grows when it is diluted, while the solute concentration stays constant.

The following is the formula for dilution of a solution:

\mathrm{M}_1 \mathrm{~V}_1=\mathrm{M}_2 \mathrm{~V}_2

here \mathrm{M}_1 , \mathrm{M}_2 represents morality and \mathrm{~V}_1 , \mathrm{~V}_2 represents volume of solution in litres (L).

We are given the values: &\mathrm{M}_1=9.0 \mathrm{M}=9.0 \mathrm{~mol} / \mathrm{L} \\&\mathrm{M}_2=3.5 \mathrm{M}=3.5 \mathrm{~mol} / \mathrm{L} \\&\mathrm{V}_2=0.45 \mathrm{~L}

Now to calculate the volume of the solution i.e. \mathrm{V}_1=\frac{\mathrm{M}_2 \mathrm{~V}_2}{\mathrm{M}_1}

$\mathrm{V}_1=\frac{3.5 \mathrm{M} \times 0.45 \mathrm{~L}}{9.0 \mathrm{M}}=0.175 \mathrm{~L}$

In milliliters $\mathrm{V}_1=0.175\mathrm{~L} \times \frac{1000 \mathrm{mL}}{1 \mathrm{L}}=175 \mathrm{~mL}$

To know more about morality of a solution, click here:

brainly.com/question/9558971

#SPJ4

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What are the three steps or formation of ionic compounds strontium and oxygen
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<h2>The three steps or formation of ionic compounds strontium and oxygen</h2>

Explanation:

Chemical bond

It is the  linkage between two or more atoms in a molecule.  

Cause of bond formation

The atoms combine with one another to achieve noble gas configuration. By doing so they become stable.  

Atom can achieve noble gas configuration  

By loosing one or more e’s.  

By gaining one or more e’s.  

By sharing one or more e’s.  

Types of CHEMICAL BONDS  

IONIC BOND (or electrovalent)  

COVALENT BOND  

Ionic bond

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It is formed when one atom donate electron & other accept electrons to achieve stable confugration.  

NOTE:  it is always formed between metal a non-metal.  

Examples :-

*  Formation of sod. Chloride as we know their atomic no., are  

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      11   17    (atomic numbers of combining atoms )

.  2, 8, (1)           2, 8, (7)   (Electronic configuration )

       Metal               non-metal                         (bond will be ionic)  

    We’ll start with metal

 Na   -   1 e-     →  Na+

          Cl    +   1e-     →  Cl-

Na     + Cl   → Na⁺ Cl⁻  

  X  

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Similarly ,for strontium and oxygen

Sr ⁸⁺     O⁸⁻

       x

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BartSMP [9]

density only changes if mass changes

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