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Anastasy [175]
2 years ago
10

How many milliliters of a 9.0 h 2so 4 solution are needed to make 0.45 l of a 3.5 m solution?

Chemistry
1 answer:
muminat2 years ago
4 0

To have 175ml is needed of a 9.0M H_{2} SO_{4} solution are needed to make 0.45 L of a 3.5 M (Morality).

<h3>How to calculate the molarity to make the solution?</h3>

The Morality unit (M) is $ \frac{\text { moles of solute }}{\text { liters of solution }}=\mathrm{mol} / \mathrm{L} $

The volume of a solution grows when it is diluted, while the solute concentration stays constant.

The following is the formula for dilution of a solution:

\mathrm{M}_1 \mathrm{~V}_1=\mathrm{M}_2 \mathrm{~V}_2

here \mathrm{M}_1 , \mathrm{M}_2 represents morality and \mathrm{~V}_1 , \mathrm{~V}_2 represents volume of solution in litres (L).

We are given the values: &\mathrm{M}_1=9.0 \mathrm{M}=9.0 \mathrm{~mol} / \mathrm{L} \\&\mathrm{M}_2=3.5 \mathrm{M}=3.5 \mathrm{~mol} / \mathrm{L} \\&\mathrm{V}_2=0.45 \mathrm{~L}

Now to calculate the volume of the solution i.e. \mathrm{V}_1=\frac{\mathrm{M}_2 \mathrm{~V}_2}{\mathrm{M}_1}

$\mathrm{V}_1=\frac{3.5 \mathrm{M} \times 0.45 \mathrm{~L}}{9.0 \mathrm{M}}=0.175 \mathrm{~L}$

In milliliters $\mathrm{V}_1=0.175\mathrm{~L} \times \frac{1000 \mathrm{mL}}{1 \mathrm{L}}=175 \mathrm{~mL}$

To know more about morality of a solution, click here:

brainly.com/question/9558971

#SPJ4

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1. What is the relationship between the concentration of the hydronium and hydroxide
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- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.

- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.

- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.

Explanation:

Hello,

It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

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In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:

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