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Anastasy [175]
2 years ago
10

How many milliliters of a 9.0 h 2so 4 solution are needed to make 0.45 l of a 3.5 m solution?

Chemistry
1 answer:
muminat2 years ago
4 0

To have 175ml is needed of a 9.0M H_{2} SO_{4} solution are needed to make 0.45 L of a 3.5 M (Morality).

<h3>How to calculate the molarity to make the solution?</h3>

The Morality unit (M) is $ \frac{\text { moles of solute }}{\text { liters of solution }}=\mathrm{mol} / \mathrm{L} $

The volume of a solution grows when it is diluted, while the solute concentration stays constant.

The following is the formula for dilution of a solution:

\mathrm{M}_1 \mathrm{~V}_1=\mathrm{M}_2 \mathrm{~V}_2

here \mathrm{M}_1 , \mathrm{M}_2 represents morality and \mathrm{~V}_1 , \mathrm{~V}_2 represents volume of solution in litres (L).

We are given the values: &\mathrm{M}_1=9.0 \mathrm{M}=9.0 \mathrm{~mol} / \mathrm{L} \\&\mathrm{M}_2=3.5 \mathrm{M}=3.5 \mathrm{~mol} / \mathrm{L} \\&\mathrm{V}_2=0.45 \mathrm{~L}

Now to calculate the volume of the solution i.e. \mathrm{V}_1=\frac{\mathrm{M}_2 \mathrm{~V}_2}{\mathrm{M}_1}

$\mathrm{V}_1=\frac{3.5 \mathrm{M} \times 0.45 \mathrm{~L}}{9.0 \mathrm{M}}=0.175 \mathrm{~L}$

In milliliters $\mathrm{V}_1=0.175\mathrm{~L} \times \frac{1000 \mathrm{mL}}{1 \mathrm{L}}=175 \mathrm{~mL}$

To know more about morality of a solution, click here:

brainly.com/question/9558971

#SPJ4

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How many mole are in 72.9g of HCI
fredd [130]
Divide by the molar mass of HCl which is 36.5g/mol grams cancels out and you are left with 1.99 mol.
3 0
3 years ago
Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation f
dmitriy555 [2]

<u>Answer:</u> The mass of cryolite produced is 51.48 kg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For aluminium oxide:</u>

Given mass of aluminium oxide = 12.5 kg = 12500 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of aluminium oxide = 101.96 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium oxide}=\frac{12500g}{101.96g/mol}=122.6mol

  • <u>For NaOH:</u>

Given mass of NaOH = 55.4 kg = 55400 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{55400g}{40g/mol}=1389mol

  • <u>For HF:</u>

Given mass of HF = 55.4 kg = 55400 g

Molar mass of HF = 20 g/mol

Putting values in equation 1, we get:

\text{Moles of HF}=\frac{55400g}{20g/mol}=2770mol

For the given chemical reaction:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)

By Stoichiometry of the reaction:

1 mole of aluminium oxide reacts with 6 moles of sodium hydroxide and 12 moles of HF.

So, 122.6 moles of aluminium oxide will react with (6\times 122.6)=735.6mol of sodium hydroxide and (12\times 122.6)=1471.2mol of HF

As, given amount of NaOH and HF is more than the required amount. So, they are considered as an excess reagent.

Thus, aluminium oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 122.6 moles of aluminium oxide will produce = \frac{2}{1}\times 122.6=245.2mol of cryolite

Now, calculating the mass of cryolite by using equation 1:

Molar mass of cryolite = 209.94 g/mol

Moles of cryolite = 245.2 mol

Putting values in equation 1, we get:

245.2mol=\frac{\text{Mass of cryolite}}{209.94g/mol}\\\\\text{Mass of cryolite}=(245.2mol\times 209.94g/mol)=51477.3g

Converting this into kilograms, we use the conversion factor:

1 kg = 1000 g

So, 51477.3 g\times (\frac{1kg}{1000g})=51.48kg

Hence, the mass of cryolite produced is 51.48 kg

7 0
3 years ago
The chemical formula for artificial sweetener is C7H5NO3S. How many carbon atoms will be found in 5 molecules of the artificial
irga5000 [103]
35

Because there’s 7 carbon atoms in every molecule of artificial sweetener

And if you have 5 molecules of that

7x5 =35
4 0
3 years ago
In order for a solute to dissolve in a solvent, what must be true?
Alex Ar [27]
The solute has to be hydrophilic, (water loving).
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Which statement about exothermic reactions are true?
Hatshy [7]

Answer:

It is either the third or fourth statement.

Explanation:

This is because exothermic reactions give off heat.

7 0
3 years ago
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