Answer:
H2SO4 + 2NaOH ---> Na2SO4 + 2H2O
Explanation:
H2SO4 + NaOH ---> Na2SO4 + H2O
Na1 ---> 2Na
H2SO4 + 2NaOH ---> Na2SO4 + H2O
2H + 2H = 4H ----> 2H
H2SO4 + 2NaOH ---> Na2SO4 + 2H2O
4O + 2O -----> 4O + 2O
Answer : The freezing point of the solution is, 260.503 K
Solution : Given,
Mass of methanol (solute) = 215 g
Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)
Freezing depression constant = ![1.86^oC/m=1.86Kkg/mole](https://tex.z-dn.net/?f=1.86%5EoC%2Fm%3D1.86Kkg%2Fmole)
Formula used :
![\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}](https://tex.z-dn.net/?f=%5CDelta%20T_f%3DK_f%5Ctimes%20m%5C%5CT%5Eo_f-T_f%3DK_f%5Ctimes%20%5Cfrac%7Bw_%7Bsolute%7D%7D%7BM_%7Bsolute%7D%5Ctimes%20w_%7Bsolvent%7D%7D)
where,
= freezing point of water = ![100^oC=273K](https://tex.z-dn.net/?f=100%5EoC%3D273K)
= freezing point of solution
= freezing point constant
= mass of solute
= mass of solvent
= molar mass of solute
Now put all the given values in the above formula, we get
![273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}](https://tex.z-dn.net/?f=273K-T_f%3D%281.86Kkg%2Fmole%29%5Ctimes%20%5Cfrac%7B215g%7D%7B%2832g%2Fmole%29%5Ctimes%20%281kg%29%7D)
By rearranging the terms, we get the freezing point of solution.
![T_f=260.503K](https://tex.z-dn.net/?f=T_f%3D260.503K)
Therefore, the freezing point of the solution is, 260.503 K