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Vlad [161]
3 years ago
12

A recipe calls for 3 cups of flour for every 5 eggs. How many cups of flour do you need for every 1 egg?

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

\boxed {\boxed {\sf \frac {3}{5} \ or \ 0.6 \ cups \ of \ flour}}

Step-by-step explanation:

Let's set up a proportion using this setup.

\frac { flour}{ eggs}=\frac { flour}{ eggs}

We know that 3 cups of flour are needed for every 5 eggs.

\frac {3 \ cups \ flour}{5 \  eggs}=\frac { flour}{ eggs}

We don't know how many cups are needed for 1 egg, so we say x cups for 1 egg.

\frac {3 \ cups \ flour}{5 \  eggs}=\frac { x \ cups \ flour}{ 1 \ egg}

\frac {3 }{5 }=\frac { x }{ 1 }

We are solving for x, so we must isolate the variable. x is being divided by 1. The inverse of division is multiplication, so multiply both sides by 1.

1*\frac{3}{5}= \frac {x}{1}*1\\

\frac{3}{5}=x

0.6=x

For every 1 egg, 3/5 or 0.6 cups of flour are needed.

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Juli2301 [7.4K]

Answer:

Distance of the trail from the start to the end is 6\frac{17}{24} miles

Step-by-step explanation:

Distance from the start of a trail to the bird lookout point=3\frac{7}{8} miles

Distance from the bird lookout point to the end of the trail =2\frac{5}{6} miles

We want to find the difference of the trail from the start to the end, that is, how far is the starting point from the end point.

The distance between the start and end points

=3\frac{7}{8}+2\frac{5}{6}\\=\frac{31}{8} +\frac{17}{6}

=\frac{161}{24} =6\frac{17}{24} miles

3 0
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Answer:

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4 0
3 years ago
Given a term and the common difference, find the explicit formula.<br> 8. a(19) = 135<br> d = 15
Rasek [7]

The explicit formula is a(n) = 15(n – 10)

<u>Solution:</u>

Given, a term a(19) = 135 and common difference d = 15

We have to find the explicit formula.

Now, we know that, a(n) = a + (n – 1)d where a(n) is nth term, a is first term, d is common difference,

So, for a(19)  

\begin{array}{l}{\rightarrow a(19)=a+(19-1) 15} \\\\ {\rightarrow 135=a+18 \times 15} \\\\ {\rightarrow a=135-270} \\\\ {\rightarrow a=-135}\end{array}

Now, we know that, an explicit formula is an expression for finding the nth term,  

So, in our problem, expression for finding nth term is a + (n – 1)d  

\begin{array}{l}{\rightarrow-135+(n-1) 15} \\\\ {\rightarrow-135+15 n-15} \\\\ {\rightarrow 15 n-150} \\\\ {\rightarrow 15(n-10)}\end{array}

Hence, the explicit formula is a(n) = 15(n – 10).

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